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mixer [17]
3 years ago
15

7,14,28,56 11th term

Mathematics
1 answer:
ololo11 [35]3 years ago
6 0
What’s that even mean
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Is y=2x+7 a function? <br> Yes or no
Kipish [7]

Answer:

YES

Step-by-step explanation:

It is because the domain doesn't repeat.

There are no multiple outcomes for one domain.

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3 years ago
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Help mewa plzzzzzzzz
Sophie [7]

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It has the same shape and angels as a trapezoid therefor it is a trapezoid

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3 years ago
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A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
3 years ago
If i multiply by 5 and subtract 63 i get the same answer if i multiply 3 and subtract 11 is the answer 26
aev [14]
Yes

26 x 5 - 63 = 67

26 x 3 - 11 = 67
3 0
3 years ago
31
VashaNatasha [74]
The answer is , c. 3.4 lol
6 0
3 years ago
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