Possible dimension of a box with a volume of 100 cubic cm
10 x 10 x 1 = 100
10 x 5 x 2 = 100
5 x 5 x 4 = 100
Surface area:
10 x 10 x 1 dimensions:
10 x 10 = 100 x 2 = 200 sq.cm
10 x 1 = 10 x 4 = 40 sq. cm
240 sq. cm * $0.05 / 100 sq.cm = $0.12 per box
0.12 per box * 100 boxes = $12
10 x 5 x 2 dimension
10 x 5 = 50 x 2 = 100 sq. cm
10 x 2 = 20 x 2 = 40 sq. cm
5 x 2 = 10 x 2 = 20 sq. cm
160 sq. cm * $0.05/100 sq. cm = $0. 08 per box
0.08 per box * 100 boxes = $8
5 x 5 x 4 dimension
5 x 5 = 25 x 2 = 50 sq. cm
5 x 4 = 20 x 4 = 80 sq. cm
130 sq. cm * $0.05/100 sq. cm = $0.065 per box
0.065 per box * 100 boxes = $6.50
The best dimension to use to have the least cost to make 100 boxes is 5 x 5 x 4. It only costs $6.50 to make 100 boxes.
The houses form a right triangle. Using a²+b²=c² you will find that the distance from Clayton’s house to Danny’s would be 4.1 miles. Adding it all up, the distance would be 9.1 miles of walking.
Answer:
x = 13
Step-by-step explanation:
The tirangle ABC is given as equilateral. Every angle is therefore =. Not only that, each angle is 60 degrees.
If you need proof of that, remember that x + x + x = 180. Every triangle has 180 degrees.
if 3x = 180 then 1 x is 60
8x - 44 = 60 Add 44 to both sides.
8x = 60 + 44
8x = 104 Divide by 8
x = 104/8
x = 13
Answer:
-4/5
Step-by-step explanation:
To find the slope of the tangent to the equation at any point we must differentiate the equation.
x^3y+y^2-x^2=5
3x^2y+x^3y'+2yy'-2x=0
Gather terms with y' on one side and terms without on opposing side.
x^3y'+2yy'=2x-3x^2y
Factor left side
y'(x^3+2y)=2x-3x^2y
Divide both sides by (x^3+2y)
y'=(2x-3x^2y)/(x^3+2y)
y' is the slope any tangent to the given equation at point (x,y).
Plug in (2,1):
y'=(2(2)-3(2)^2(1))/((2)^3+2(1))
Simplify:
y'=(4-12)/(8+2)
y'=-8/10
y'=-4/5
Answer:
Starting time: 1:37
Step-by-step explanation:
Instead of proof to solve the problem, let us prove that the starting time above is correct;
1. There are 60 minutes in an hour, so 60 - 37 = the minutes 'till 2:00, or 23 minutes
2. Knowing that the time the truck stopped driving through the neighborhood was 5 minutes past 2:00, the minute difference being 23 + 5, or <em>28 minutes</em>
<em>Proved: 28 minutes</em>
