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2 years ago

The total cost of 4 starfish was $7.20. Write and solve an equation to find how much one starfish cost.

Mathematics

1 answer:

Lyrx [107]2 years ago

7 0

Answer:

$1.80

Step-by-step explanation:

4x = 7.20

x = 1.80

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In an arithmetic sequence, a3=15 and a8=0. What is the value of a5?

grin007 [14]

The value of a5 is 9

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3 years ago

What is 5 divided by 2930

Anna007 [38]

It would be: 5/2930 = 0.0017

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3 years ago

Two cylinders are shown below which cylinder has a greater volume use 3.14 for pi

lesya [120]

Answer:

Cylinder Q has a greater volume

Step-by-step explanation:

For this question we need to utilise the volume of a cylinder which is

→ Volume of a cylinder = π × r² × h

Let's substitute in the values and then do the analysis

Cylinder P

→ Volume of a cylinder = π × r² × h

⇒ Substitute in the values

→ Volume of a cylinder = π × 4.25² × 14

⇒ Simplify

→ Volume of a cylinder = 794.430242277

The volume of cylinder P is 794.430242277

-------------------------------------------------------------------------------------------------------

Cylinder Q

→ Volume of a cylinder = π × r² × h

⇒ Substitute in the values

→ Volume of a cylinder = π × 7² × 8.5

⇒ Simplify

→ Volume of a cylinder = 1308.47334022

The volume of cylinder Q is 1308.47334022

-------------------------------------------------------------------------------------------------------

We can see that cylinder Q has a greater volume

8 0

3 years ago

A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey

Lubov Fominskaja [6]

Answer:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

Step-by-step explanation:

For this case we have the following distribution given:

X 0 1 2 3 4 5 6

P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02

For this case we need to find first the expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And replacing we got:

$E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61$

Now we can find the second moment given by:

$E(X^2) =\sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97$

And the variance would be given by:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

8 0

3 years ago

Is k6= a solution or non solution

mrs_skeptik [129]

I think it will be a solution. Hope it help!

6 0

3 years ago

Read 2 more answers