Question

A jar made of 3/16-inch-thick glass has an inside radius of 3.00 inches and a total height of 6.00 inches (including the bottom thickness of glass). The glass has a density of 165 lb/ft3. The jar is placed in water with a density of 62.5 lb/ft3.
Assume the jar sits upright in the water without tipping over. How far will the empty jar sink into the water?

a. What is the volume of the glass shell of the jar? Precision 0.00
b. What is the weight of the jar? Precision 0.00
c. What is the weight of water the empty jar will displace? Precision 0.00
d. What is the volume of water the empty jar will displace? Precision 0.00
e. How far will the empty jar sink?

Answer 1

Answer:

a) 0.012ft³

b)2.09 lb

c)0.791 lb

d) 0.012ft³

e) 6 inches

Step-by-step explanation:

a) To determine the volume of the shell of the jar we must determine the volume of the hollow cylinder:

$V=3.1416\cdot{h}\cdot{(R^2-r^2)$

Where r is the inside radius and R the outer radius.

$V=3.1416\cdot{6}\cdot{(3.1875^2-3^2)=21.87$

convert to cubic ft:

$=21.87\cdot{0.0005787}=0.01266$

The volume of the glass shell is 0.012 ft³

b) The weight of the cylinder can be determined because we have the volume and the density. Weight is defined as the product of volume and density:

$M=p\cdot{v}=165\cdot{0.01266}=2.09$

The weight of the jar is 2.09 lb

c) The displacement of water is just the density of water mutliplied by the volume of the jar:#

$=0.01266\cdot{62.5}=0.79$

0.791 lb of water will be displaced.

d) The volume of the water displaced is:

[tex]=0.791/62.5=0.01266

e) The jar will be fully submerged because the density of the jar is larger than water.