Answer:
the woman has to live 1 mile from work to minimize the expenses
Step-by-step explanation:
Given the data in the question;
the distance within 9 miles ⇒ 0 < x > 9
Total costs Q = cx + 4c/( x + 1)
costs should be minimum ⇒ dQ/dx = 0
⇒ d/dx [ cx + 4c/( x + 1) ] = 0
⇒ ( x + 1)² = 4
take square root of both side
√[ ( x + 1)² ] = √4
x + 1 = 2
x = 2 - 1
x = 1
Therefore, the woman has to live 1 mile from work to minimize the expenses
Answer: The two sides are 15m and 10m.
Step-by-step explanation:
Area = l x w
150 = l x w
There are two solutions for l
l 1= P/4+1/4√P2﹣16A
=50/4+1/4·√50^2﹣16·150=15m
l2 = P/4﹣1/4√P2﹣16A
=50/4﹣1/4·√50^2﹣16·150=10m
Answer is 7/16.
Add number of fruit total to get denominator. Add number of oranges and pears to get numerator.
Answer:
Zeroes: None
Domain: All real numbers
Maximum: None
Step-by-step explanation:
EDGE PRECAL 2020
