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Anastasy [175]
3 years ago
10

LF U DO THIS ILL GIVE BRAINLIEST AND MAKE A SPECIAL QUESTION WITH ALL MY POINTS THANKS SO MUCH

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
3 0

Answer:

that table is for you can put some question crime then you need to find the clime and then you need to think how that pass and then you can put any evidence like a gun or a shirt like a evidence and the you will tell how that pass like he go in the house and then he have a gun and then he kill something like that

Step-by-step explanation:

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What is 36/48 simplifiied?
Sunny_sXe [5.5K]
36/48 simplified is 3/4

divide both by 12
36÷12
3
48÷12
4
3 0
3 years ago
Read 2 more answers
Cos(2α)*sin(α-β)-cos(β-α)*sin(2α)
Hunter-Best [27]

Answer:

Step-by-step explanation:

cos (2α)*sin (α-β)-cos(β-α)*sin(2α)
cos (β-α)=cos {-(α-β)}=cos (α-β)

[cos (-x)=cos x]

sin(α-β)*cos (2α)-cos (α-β)*sin (2α)=sin (α-β-2α)=sin (-α-β)

=sin {-(α+β)}

=-sin (α+β)

6 0
3 years ago
What is (5x-2)(4x^2 -3x-2)
Ronch [10]
Answer: 20x^3 - 23x^2 - 4x + 4

Explanation:

Use distributive property:

(5x-2)(4x^2 - 3x-2)
= 20x^3 - 15x^2 - 10x - 8x^2 + 6x + 4
= 20x^3 - 23x^2 - 4x + 4
8 0
3 years ago
Read 2 more answers
Write your question here keep it simple and clear
igor_vitrenko [27]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

12 + 12 + 18 + 18 = 60

The perimeter is 60 cm

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

7 0
3 years ago
The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

x+y=5600...(1)

y=5600-x...(1)    

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be 40x and cost of y end-zone tickets would be 20y.

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

40x+20y=134000...(2)

Upon substituting equation (1) in equation (2), we will get:

40x+20(5600-x)=134000

40x+112000-20x=134000

20x+112000=134000

20x+112000-112000=134000-112000

20x=22000

\frac{20x}{20}=\frac{22000}{20}

x=1100

Therefore, 1100 field side tickets were sold.

Upon substituting x=1100 in equation (1), we will get:

y=5600-1100

y=4500

Therefore, 4500 end-zone tickets were sold.

3 0
3 years ago
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