Answer:
150
Step-by-step explanation:
Length times width you learned about that in elementary school every one has.
Using proportions, it is found that there is a 0.54 = 54% probability that a randomly selected household owns a cat.
<h3>What is a proportion?</h3>
A proportion is a fraction of total amount.
In this problem, the proportions associated with owning a cat are given by:
- 70% of 60%(also have a dog).
- 30% of 40%(do not have a dog).
Hence:
p = 0.7(0.6) + 0.3(0.4) = 0.42 + 0.12 = 0.54.
0.54 = 54% probability that a randomly selected household owns a cat.
More can be learned about proportions at brainly.com/question/24372153
Answer:
See below
Step-by-step explanation:
<u>Parent function:</u>
<u>Translation rule:</u>
It will translate right 3 units and up 1 unit
<u>The translated function is:</u>
- f(x) = + 1
Graph is attached where dotted blue is parent function and solid red is translated function
7:8 would increase a picture the most because it would be increase the size.
Hope this helps! :)
The probability of having lunch together is p = 40% = 0.4
The probability of not having lunch together is q = 1 - p = 0.6
Number of trials (days in a week) is n = 7
Let r = number of days in the week when Andy and Anna have lunch together.
Use th graphing calculator to obtain
P(6 of 7) = ₇C₆ (0.4)⁶(0.6) = 0.017
P(7 of 7) = ₇C₇ (0.4)⁷(0.6)⁰ = 0.002
Therefore
P(at least 6 of 7) = P(1 of 7) + P(2 of 7) + ... + P(6 of 7)
= 0.131 + 0.261 + 0.290 + 0.194 + 0.077 + 0.017
= 0.97 or 97%
P(at least 6 of 7) = 0.017 + 0.002 = 0.019 = 1.9%
P(exactly 6 of 7) = 0.017 or 1.7%
Answer:
The probability of having lunch at least 6 days per week is 0.019 or 1.9%.
The probability of having lunch exactly 6 times is 0.017 or 1.7%