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tekilochka [14]
2 years ago
5

A point is reflected across the y-axis. Jimmy says that the reflected point is \left(3.5,6\right), which means the original poin

t was \left(3.5,-6\right). Is Jimmy's statement true or false?
Mathematics
1 answer:
levacccp [35]2 years ago
7 0

Given:

A point is reflected across the y-axis. The reflected point is (3.5,6).

Jimmy says the original point is (3.5,-6).

To find:

Whether Jimmy's statement true or false

Solution:

If a point is reflected across the y-axis, then y-coordinate remains same but change the sign of x-coordinate.

(x,y)\to (-x,y)

If the reflected point is (3.5,6), then the original point must be (-3.5,6), which is not equal to (3.5,-6).

Therefore, Jimmy's statement is false.

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5 0
2 years ago
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If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
2 years ago
Suppose it is found that a certain model of car sells y= -1.6(x-2)^2 + 4.8(x-2) + 16 cars per week, where x is the number of sho
Vilka [71]

Answer:

Approximately 4 shops would be the best number of shops which the car is sold, and the number of cars is 20.

Step-by-step explanation:

This is a quadratic function. Therefore, the first thing you need to do is assume some values for x, and then, calculate the value of y, (which would be the number of cars sold). In this way, you can do the graph.

Watch the following attachment, which is a document of excel, showing the graph and some values of x, that I assume

Now, even if you don't have the graph you can estimate the number of shops with the following expression of the summit:

X = -b / 2a

Where:

a: number that goes along with the x elevated.

b: number that goes along with the x, but without being elevated.

In this equation, the first thing we need to do, is rearrange it, that's because we have a (x-2) in the equation, and this could be really annoying.

First let's solve the (x-2)^2

(x-2)^2 = (x-2)(x-2) = x^2 - 2*2x + 2^2 = x^2 - 4x + 4

This is now multiplied by -1.6:

-1.6x^2 + 6.4x - 6.4

Now, multiply 4.8 by x-2:

4.8x - 9.6

Finally, let's arrange this:

-1.6x^2 + 6.4x - 6.4 + 4.8x - 9.6 + 16

-1.6x^2 + 11.2x - 6.4 - 9.6 + 16 = -1.6x^2 + 11.2x

This means that the graph do not have a "y" intercept, and the values of a and b are -1.6 and 11.2, therefore, we can estimate the best number of shops, calculating the summit of the graph (This is because s a quadratic function, and the graph is a parable, and the minimum or maximum point of the graph is reached in the summit)

Summit has X and Y values, the x value is (see formula above):

X = -11.2 / 2 * -1.6 = 3.5

and for the y value, just replace the X value in the equation:

Y = -1.6(3.5)^2 + 11.2(3.5) = -19.6 + 39.2 = 19.6

With this we can conclude that the best number of shops that sells this model of car, is 4 (rounded) and they all sell 20 cars (also rounded). See the graph below in the attachment.

Download xlsx
4 0
3 years ago
Read 2 more answers
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