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3 years ago

Find the measure of Angle BAD It’s timed and I need the grade plee

Mathematics

1 answer:

marishachu [46]3 years ago

6 0

What does angle bad mean

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Find m ABC (2x+14) (x+7)

Orlov [11]

Answer:

Last option 30°

damm sure about it

Step-by-step explanation:

value of x is 23 but value of Angle ABC will be x +7 i.e. 30

6 0

2 years ago

Read 2 more answers

PLS ANSWER I WILL GIVE YOU BRAINLIST AND A THANK YOU!!

Arte-miy333 [17]

Answer:

x=45

Step-by-step explanation:

2x+45+x=180

Combine 2x and x to get 3x.

3x+45=180

Subtract 45 from both sides.

3x=180−45

Subtract 45 from 180 to get 135.

3x=135

Divide both sides by 3.

x=135/3

Divide 135 by 3

x=45

8 0

3 years ago

Sketch the domain D bounded by y = x^2, y = (1/2)x^2, and y=6x. Use a change of variables with the map x = uv, y = u^2 (for u ?

cluponka [151]

Under the given transformation, the Jacobian and its determinant are

$\begin{cases}x=uv\\y=u^2\end{cases}\implies J=\begin{bmatrix}v&u\\2u&0\end{bmatrix}\implies|\det J|=2u^2$

so that

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\iint_{D'}\frac{2u^2}{u^2}\,\mathrm du\,\mathrm dv=2\iint_{D'}\mathrm du\,\mathrm dv$

where $D'$ is the region $D$ transformed into the $u$ - $v$ plane. The remaining integral is the twice the area of $D'$ .

Now, the integral over $D$ is

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\left\{\int_0^6\int_{x^2/2}^{x^2}+\int_6^{12}\int_{x^2/2}^{6x}\right\}\frac{\mathrm dx\,\mathrm dy}y$

but through the given transformation, the boundary of $D'$ is the set of equations,

$\begin{array}{l}y=x^2\implies u^2=u^2v^2\implies v^2=1\implies v=\pm1\\y=\frac{x^2}2\implies u^2=\frac{u^2v^2}2\implies v^2=2\implies v=\pm\sqrt2\\y=6x\implies u^2=6uv\implies u=6v\end{array}$

We require that $u>0$ , and the last equation tells us that we would also need $v>0$ . This means $1\le v\le\sqrt2$ and $0$ , so that the integral over $D'$ is