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bonufazy [111]
3 years ago
5

WORTH 19 POINTS!!

Mathematics
1 answer:
marta [7]3 years ago
8 0
You have to make a cos graph that starts its minimum and of -2, has an amplitude of 10, a period of 10 and  a maximum of 18.
I decided to use a cos graph since cos graphs start at their minimum or maximum unlike a sine graph that starts halfway between the minimum and maximum.  You also know the amplitude has to be 10 since 18+2=20 and 20/2=10.  We were also told that the water wheel completels a rotation every 10 minutes which means the period is 10 minutes.

lets start of with a regular cos(x) graph.  This starts on its maximum instead of minimum so we have to multiply it by -1 to get -cos(x) which does start on its minimum.

-cos(x) has an amplitude of 1 instead of 10, to fix that we multiply it by 10 to get -10cos(x) which has an amplitude of 10.
 
-10cos(x) has a period of 2π instead of 10, to fix this we multiply the x by 2π/10 to get -10cos((π/5)x) which now has a period of 10.

-10cos((π/5)x) has a minimum of -10 and maximum of 10 instead of a minimum of -2 and maximum of 18, to fix this we add 8 to -10cos((π/5)x) to get -10cos((π/5)x)+8 which does have a minimum of -2 and maximum of 18.

Therefore the answer is y=-10cos((π/5)x)+8. x being time in minutes and and y being the height in feet.  

I hope this helps.  Let me know if anything is unclear.
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Dmitrij [34]

The rest of the band drove more and by 6 miles.

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3 years ago
Evaluate the function at the given numbers( correct to six decimal places). Use the results to guess the value of the limit or e
netineya [11]

Answer:

Value of the limit is 0.5.

Step-by-step explanation:

Given,

F(x)=\frac{e^x-1-x}{x^2}

When,

x=1,F(1)=frac{e^1-1-1}{1}=e-2=0.718281

x=0.5, F(0.5)=\frac{e^0.5-1-0.5}{(0.5)^2}=0.594885

x=0.1, F(0.1)=\frac{e^0.1-1-0.1}{(0.1)^2}=0.517091

x=0.05, F(0.05)=\frac{e^0.05-1-0.05}{(0.05)^2}=0.508438

x=0.01, F(0.01)=\frac{e^0.01-1-0.01}{(0.01)^2}=0.501670 \hfill (1)

Correct upto six decimal places.

Now,

\lim_{x\to 0}F(x)=\lim_{x\to 0}\frac{e^x-1-x}{x^2}   (\frac{0}{0}) form, applying L-Hospital rule that is differentiating numerator and denominator we get,

\lim_{x\to 0}F(x)

=\lim_{x\to 0}\frac{e^x-1}{2x}    (\frac{0}{0}) form.

=\lim_{x\to 0}\frac{e^x}{2}=\frac{1}{2}=0.5\hfill (2)

Limit exist and is 0.5. That is according to (1) we can see as the value of x lesser than 1 and tending to near 0, value of the function decreases respectively. And from (2) it shows ultimately it decreases and reach at 0.5, consider as limit point of F(x).  

8 0
3 years ago
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-Dominant- [34]

Answer:

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PLEASE HELP!!!
just olya [345]

Answer:

-3(1.5n - 1)

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Marys family had to pay 3$ for the car plus 2$ for each number of people in the car.
Gala2k [10]

Answer:

y=2x+3

Step-by-step explanation:

Y is the total amount that the family pays. 2x represents 2 dollars for every person (so, 2 multiplied by the number of people). Finally, 3 represents the initial amount that they must pay, no matter how many are in the car.

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