- The kinetic energy of the cart at point A is zero and the potential energy is 58,800 J.
- The kinetic energy of the cart at point B is 9,800 J and the potential energy is 49,000 J.
- The velocity of the cart at point B is 9.9 m/s.
<h3>Kinetic and potential energy at point A and B</h3>
At maximum height, velocity is zero and kinetic energy will be zero.
K.E(A) = 0
P.E(A) = mgh = 200 x 9.8 x 30 = 58,800 J
K.E(B) = P.E(A) - P.E(B)
K.E(B) = 58,800 J - (200 x 9.8 x 25)
K.E(B) = 58,800 J - 49,000 J
K.E(B) = 9,800 J
<h3>Velocity at point B</h3>
K.E = ¹/₂mv²
v² = 2K.E/m
v² = (2 x 9800)/(200)
v² = 98
v = √98
v = 9.9 m/s
Learn more about kinetic energy here: brainly.com/question/25959744
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when wire is added short Circuit occurs makes bulb 1 and 2 turn off but keeps bulb 3 and 4 on .
Answer:
Velocity = 15.87m/s
Explanation:
Given the following data;
Distance, d = 200000m
Time, t = 12600secs
*To find the velocity*
Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.
Mathematically, velocity is given by the equation;
![Velocity = \frac{distance}{time}](https://tex.z-dn.net/?f=Velocity%20%3D%20%5Cfrac%7Bdistance%7D%7Btime%7D)
Substituting into the equation, we have;
![V = \frac{200000}{12600}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B200000%7D%7B12600%7D)
Velocity = 15.87m/s
<em>Therefore, the velocity of the car is 15.87 meters per seconds due west.</em>
Im pretty sure the answer would be A