Question

13. A diver swims to a depth of 3.2 m in a freshwater lake. What is the increase in the force pushing in on her eardrum, compared to what it was at the lake surface? The area of the eardrum is 0.60 cm².

Answer 1

Answer:

1.88 N

Explanation:

h = 3.2 m, A = 0.6 cm^2 = 0.6 x 10^-4 m^2

density of water, d = 1000 kg/m^3, g = 9.8 m/s^2

Pressure at depth h, P = h x d x g = 3.2 x 1000 x 9.8 = 31.36 x 10^3 Pa

Force = pressure x Area = 31.36 x 10^3 x 0.6 x 10^-4 = 1.88 N

Thus, the force on ear drum is 1.88 N.