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3 years ago

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The center of a moon of mass m is a distance D from the center of a planet of mass M. At some distance x from the center of the

planet, along a line connecting the centers of planet and moon, the net force on an object will be zero. Natividad, Joshua - [email protected] @theexpertta - tracking id: 1F76-1A-38-41-94BC-19489. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account. show answer No Attempt 50% Part (a) Derive an expression for x.

1 answer:

seraphim [82]3 years ago

6 0

Answer:

$x=\dfrac{D}{1+\sqrt{\dfrac{m}{M}}}$

Explanation:

Mass of moon = m

Mass of planet =M

We know that gravitational force given as

$F=G\dfrac{m_1m_2}{d^2}$

$F'=G\dfrac{m'M}{x^2}$

$F=G\dfrac{m'm}{(D-x)^2}$

Given that force is zero so

F=F'

$G\dfrac{m'm}{(D-x)^2}=G\dfrac{m'M}{x^2}$

$\dfrac{m}{(D-x)^2}=\dfrac{M}{x^2}$

$\dfrac{x}{D-x}=\sqrt{\dfrac{M}{m}}$

$\dfrac{D-x}{x}=\sqrt{\dfrac{m}{M}}$

$x=\dfrac{D}{1+\sqrt{\dfrac{m}{M}}}$

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A proton (mass=1.67x10^-27 kg, charge= 1.60x10^-19 C) moves from point A to point under the influence of an electrostatic force

Tom [10]

Answer:

$VB - VA = - 33.4$

Explanation:

Generally the workdone in moving the proton is mathematically represented as

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So

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Here $v_a$ is the velocity at A with value 50 m/s

So

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$KE_i = 2.09 *10^{-24} \ J$

Also

$KE_f = \frac{1}{2} m v_b^2$

Here $v_a$ is the velocity at A with value $80 km/s = 80000 m/s$

=> $KE_f = \frac{1}{2} (1.67*10^{-27}) * 80000^2$

=> $KE_f = 5.34 *10^{-18} \ J$

So

$W = 5.34 *10^{-18} - 2.09 *10^{-24}$

$W = 5.34 *10^{-18} m/s$

Now this workdone is also mathematically represented as

$W = q * V$

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$q * V = 5.34 *10^{-18}$

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Generally proton movement is in the direction of the electric field it means that $VA>VB$

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$VB - VA = - 33.4$

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Answer:

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Explanation:

You are camping in the breathtaking mountains if Colorado. You spy an unopened diet soda can floating motionless below the surface of a lake. What is the direction and amount of force the water exerts on it?

A. Zero

B. Down, equal to the can's weight

C. Up, equal to the can's weight

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sladkih [1.3K]

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A merry-go-round is spinning at a rate of 4.04.0 revolutions per minute. Cora is sitting 0.50.5 m from the center of the merry-g

dsp73

Answer:

angular speed of both the children will be same

Explanation:

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