Momentum in x-axis before collision: 4.5 x 1.5 = 6.75
Momentum in x-axis after collision: 1.5 x 2.1 x cos(30) + 3.2 x v x cos(30)
By the principle of conservation of momentum, these are equal:
6.75 = 2.73 + 2.77v
v = 1.45 m/s
Answer:
0.21 m/s/s.
Explanation:
Whenever there is an action force acting on a body, there will be a reaction force.
Here the force with which the astronaut throws the tool is given as 16 N.
Force is measured in newtons and is equal to the rate of change of momentum.
Since the astronaut has a mass, she experience a reaction force. It is given by F = ma, according to Newton's 2nd law.
16 = 75 a
⇒ Acceleration = a = F/m = 16/75 = 0.21 m/s/s
Answer:
v=1.295
Explanation:
What we are given:
a=5÷(3s^(1/3)+s^(5/2)) m/s^2
Start by using equation a ds = v dv
This problem requires a numeric method of solving. Therefore, you can integrate v ds normally, but you must use a different method for a ds The problem should look like this:
<em>a=2</em>
<em>b=1</em>
<em>x=5÷(3s^(1/3)+s^(5/2)) </em><em>m/s^2</em>
<em>dx=dv</em>
Integrate the left side the standard method.
<em>a=v</em>
<em>b=0</em>
<em>dx=dv</em>
<em>Integrating</em>
=v^2/2
Use Simpson's rule for the right site.
<em>a=b</em>
<em>b=a</em>
<em>x=f(x)</em>
f(x)=b-a/6*(f(a)+4f(a+b/2)+f(b)
If properly applied. you should now have the following equation:
v^2/2=5[(1/6*(0.25+4(0.162)+(0.106)]
=0.8376
Solve for v.
v=1.295
Explanation:
Acceleration is change in velocity over time.
a = Δv / Δt
a = (18.0 m/s − 0 m/s) / (6.00 s)
a = 3.00 m/s²
Momentum is mass time velocity.
p = mv
p = (8000 kg) (18.0 m/s)
p = 144,000 kg m/s
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