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Ganezh [65]
3 years ago
13

The train traveled 500 kilometers north to Odessa in 2 hours . What’s the train’s speed ? What is the velocity ?

Physics
1 answer:
ElenaW [278]3 years ago
7 0

Explanation:

Speed is distance over time.

500 km / 2 hr = 250 km/hr

Velocity is speed and direction.

250 km/hr north

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3. A force of 90N pushes downward at an angle of 32° to the horizontal on an object resting on the floor. The
Nonamiya [84]

F = m × g

Now when, a force acts on the object at an angle and in downwards, thus formula becomes:

= N = mg + F sin(x)

Here,

  • N = normal force, m = mass , g = acceleration due to gravity, F = outside force, x = the angle formed

See, as we habe to calculate the weight, which is m × g, thus we will recreate thus formula like thus:

= N = w + F sin(x) --------- [Weight = w]

Now, the solutions becomes easy from here, just put the values:

= N = w + F sin(x)

= 200 = w + 90 × sin(32)

= 200 = w + 90 × 0.55

= 200 = w + 49.5

= 200 - 49.5 = w

= 150.5 = w

I have got my answer but in approx, hope you will not mind. ^^"

8 0
3 years ago
The farther you bring charged objects​
stiks02 [169]

Answer:

Weaker, stronger

Explanation:

hope this helped!

3 0
3 years ago
Read 2 more answers
A diffraction grating has 300 lines per mm. If light of wavelength 630 nm is sent through this grating, what is the highest orde
True [87]

Answer:

The order of maximum is   n = 5

Explanation:

From the question we are told that

  The  diffraction grating is  k  =  300 lines per mm  =  300000 lines per m

   The wavelength is  \lambda  =  630 \  nm  =  630 *10^{-9} \  m

   Generally the condition for constructive interference is mathematically represented as

      dsin \theta = n  * \lambda

Here n is the order maximum

d is the distance the grating which is mathematically represented as

    d =  \frac{1}{k}

=>   d =  \frac{1}{300000}

=>    d =  3.3*10^{-6}\  m

So

   n  = \frac{dsin \theta}{ \lambda}

at maximum  sin\theta  =  1

     n  = \frac{d}{\lambda}

=>   n  = \frac{3.3*10^{-6}}{630 *10^{-9}}

=>   n = 5

 

8 0
3 years ago
a runner moves 2.88 m/s north. she accelerates at 0.350 m/s2 at -52.0 angle. at the point where she is running directly east, wh
Naily [24]

Answer:

11.7 m

Explanation:

I assume north is the y direction and x is the east direction, so Δx refers to the displacement in the east direction.

First, find the time it takes for the velocity to change from directly north to directly east.

Given (in the y direction):

v₀ = 2.88 m/s

v = 0 m/s

a = 0.350 m/s² sin(-52.0°) = -0.276 m/s²

Find: t

v = at + v₀

(0 m/s) = (-0.276 m/s²) t + (2.88 m/s)

t = 10.4 s

Given (in the x direction):

v₀ = 0 m/s

a = 0.350 m/s² cos(-52.0°) = 0.215 m/s²

t = 10.4 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (10.4 s) + ½ (0.215 m/s²) (10.4 s)²

Δx = 11.7 m

7 0
3 years ago
Change in temperature of body is 50°C the change in temperature on Kelvin scale is?<br> Ans is 5oK
nata0808 [166]
The changes in celsius are the same as those in kelvins. the difference between the two scales is that 0 celsius is about 273 kelvins and that 0 kelvins is about -273 celsius (note the minus sign)
3 0
4 years ago
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