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olya-2409 [2.1K]
3 years ago
9

Need Help with some Math

Mathematics
1 answer:
tatyana61 [14]3 years ago
4 0

Answer:

8

Step-by-step explanation:

We can use the Polynomial Remainder Theorem. The PRT states that if we have a polynomial f(x) being divided by a factor in the form of (x-a), then the remainder of the polynomial is given by f(a).

We have the polynomial:

f(x)=3x^{15}-5x^{12}+7x^6-3x^2+12

And it is being divided by:

(x+1)

We can rewrite our factor as:

(x-(-1))

Therefore:

a=-1

Then our remainder will be:

f(-1)

Evaluate:

\begin{aligned} f(-1)&=3(-1)^{15}-5(-1)^{12}+7(-1)^6-3(-1)^2+12\\&=-3-5+7-3+12\\&=8 \end{aligned}

So, our remainder will be 8.  

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Answer:

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Rewrite the expression x^3+10x^2+13x+39/x^2+2x+1 in the form of q(x)+r(x)/b(x)
natima [27]

\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}

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8x^2=8\cdot x^2, and 8(x^2+2x+1)=8x^2+16x+8. Subtracting this from the previous remainder gives a new remainder of

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-84x is not a multiple of x^2, so we're done. Then

\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}=x+8+\dfrac{-4x+31}{x^2+2x+1}

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3 years ago
What is a formula for the nth term of the given sequence?<br> 20,50, 125...
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Answer:

a(n) = 20*2.5^(n - 1)

Step-by-step explanation:

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