Answer:
1r
Step-by-step explanation:
(5r-4)(2r-6r+4)
1(5r-4)+1(2r-6r+4)
5r-4+2r-6r+4
5r+2r-6=1r
1r-4+4
-4+4=0
1r
Answer:
CD is 6 cm and DE is 4 cm.
Step-by-step explanation:
Well it‘s the correct answer and I got it right so good luck out there bois!
We know that
At sea level, the height is 0 and
the pressure is 98 kilopascals
At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%
</span>i(100%-11.41%)/100----> (0.8859)
therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals
the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
Answer:
It is vertically stretched by a factor of 200 and shifted 10 units up.
Step-by-step explanation:
cool like that
The perimeter = 4 * length of a semicircle of radius 5 == 4* pi * 5 = 20 pi cm
The area of one of the clear parts = 1/2 area of square - area semicircle
= 1/2 * 10^2 - 1/2 pi *5^2 = 50 - 12.5pi
So area of shaded parts = area of square - 4 (50 - 12.5pi)
= 100 - 200 + 100pi = (100pi - 100) cm^2
