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aev [14]
3 years ago
6

At $13.35 per pound, what is the value of 4 pounds of crab legs

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
7 0
$53.40 is 4lb of crab legs
Bro you just gotta multiply $13.35x4=$53.40
Eddi Din [679]3 years ago
4 0
If there 4 pounds and each pound is 13.35 ,you should multiply 4 times 13.35 which is $53.40
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The area of a rectangular field is 7050m^2. If the width of the field is 75m, what is its length?
sweet [91]

Answer:

Step-by-step explanation: Area =length × width

7050m^2 = X× 75m

7050 =75X

Divide both sides by 75

7050÷75 =75÷75

74m= X

3 0
2 years ago
Have to find volume and surface area but idk how
Setler [38]

Answer:

volume 1050 in^{3}

surface area 859 in^{2}

Step-by-step explanation:

volume is length times width times height (7*25*12)/2

surface area is area of all the sides added together

2(25*12)+(12*7)+ 2(\frac{7*25}{2})

4 0
3 years ago
Read 2 more answers
Which function is nonlinear?
lutik1710 [3]

Answer:

(-1,5), (0,4) ,(1,3) ,(3,1) is linear so dont pick it

(-4,-7), (-2,-6), (2,-4), (4,-3) is linear

you know what I'll just say it wait a minute is there like a other option

Step-by-step explanation:

U can tell by graphing them out yourself and if u see a straight line then it linear, and if you see a curved loop then it's non- linear. but I'll do it :)

4 0
3 years ago
In a standard deck of cards there 52 cards of which 26 are black and 26 are red. Additionally, there are 4 suits, hearts, clubs,
stich3 [128]

Using probability concepts, it is found that P(S and D) = 0.1275.

-----------------------

  • A probability is the <u>number of desired outcomes divided by the number of desired outcomes</u>.
  • In a standard deck, there are 52 cards.
  • Of those, 13 are spades, and 13 are diamond.

  • The probability of selecting a spade with the first card is 13/52. Then, there is a 13/51 probability of selecting a diamond with the second. The same is valid for diamond then space, which means that the probability is multiplied by 2. Thus, the desired probability is:

P(S \cap D) = 2 \times \frac{13}{52} \times \frac{13}{51} = \frac{2\times 13 \times 13}{52 \times 51} = 0.1275

Thus, P(S and D) = 0.1275.

A similar problem is given at brainly.com/question/12873219

7 0
2 years ago
First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
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