Ok so only need help wth these...

A bank paid 2.3% interest on a money market account. What is 2.3% written as a decimal

DochEvi [55]

$1\%\ \ \rightarrow\ \ \frac{1}{100}=0.01 \\\\2.3\%\ \ \rightarrow\ \ x\\\\x= \frac{2.3\%\cdot0.01}{1\%} \ \ \ \Rightarrow\ \ \ x=0.023$

7 0

3 years ago

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Mastery challenge

kolezko [41]

The complete question is;

Below are last week's revenues (in thousands of dollars) for six different Nancy's Noodles locations. 6, 6.8,3.7,8.1,6.6,7

Find the median revenue.

Answer:

Median = 6.7 thousand dollars

Step-by-step explanation:

From the question, the 6 revenues in thousands of dollars are;

6, 6.8, 3.7, 8.1, 6.6, 7

To find the median, we need to arrange the terms in ascending order.

Thus, we have;

3.7, 6, 6.6, 6.8, 7, 8.1

Since the number of terms are 6,then the median term is (6 + 1)/2 = 7/2 = 3.5th term

To get the 3.5th term, we have to find the average of the 3rd and 4th terms in the series of revenue.

3rd term = 6.6 and 4th term = 6.8

Thus, median = (6.6 + 6.8)/2

Median = 13.4/2

Median = 6.7 thousand dollars

7 0

3 years ago

On one day in January, the temperature in Milwaukee, Wisconsin fell 12°F from the high temperature to a low temperature of -8°F.

tatiyna

Answer:

t = 4

Step-by-step explanation:

you have -8 and twelve you equation is x -12 = -8 so we just have to flip the equation around to make it x = 12 -8 which is easy . You just have to make sure you don't get mixed up while flipping the signs.

5 0

3 years ago

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Help evaluating the indefinite integral

Dafna11 [192]

Answer:

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$

General Formulas and Concepts:
Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]:
$\displaystyle (cu)' = cu'$

Derivative Property [Addition/Subtraction]:
$\displaystyle (u + v)' = u' + v'$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Reverse Power Rule]:
$\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]:
$\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution/u-solve.

Set u:
$\displaystyle u = 4 - x^2$
[u] Differentiate [Derivative Rules and Properties]:
$\displaystyle du = -2x \ dx$
[du] Rewrite [U-Solve]:
$\displaystyle dx = \frac{-1}{2x} \ du$

Step 3: Integrate Pt. 2

[Integral] Apply U-Solve:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du$
[Integrand] Simplify:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du$
[Integral] Rewrite [Integration Property - Multiplied Constant]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du$
[Integral] Apply Integration Rule [Reverse Power Rule]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C$
[u] Back-substitute:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$