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Sergeeva-Olga [200]
4 years ago
14

Math Help Please

Mathematics
1 answer:
elena55 [62]4 years ago
3 0
1) In order to solve the equation n/6 = -11.9, you must multiply by 6.

2) -9m = -45 \\ \\ m =  \frac{-45}{-9} \\ \\ m =  \frac{45}{9} \\ \\ m = 5 \\ \\ Answer: \fbox {m = 5}

3) -14 =  \frac{u}{8} \\ \\ -14 \times 8 = u \\ \\ -112 = u \\ \\ u = -112 \\ \\ Answer: \fbox {u = -112}

4) -117 = -9h \\ \\  \frac{-117}{-9} = h \\ \\  \frac{117}{9} = h \\ \\ 13 = h \\ \\ h = 13 \\ \\ Answer: \fbox {h = 13}

5)\frac{q}{19} = 5 \\ \\ q = 5 \times 19 \\ \\ q = 95 \\ \\ Answer: \fbox {q = 95}
You might be interested in
Need help please and fast thank you
shtirl [24]

Answer:

The second batch

Step-by-step explanation:

7 0
3 years ago
Simon and his niece Marcie are comparing their ages to see if there is a Mathematical connection. They find that Simon is three
Rom4ik [11]

Answer:

Simon's Age = 47

Marcie's Age = 11

Step-by-step explanation:

<em>The question is to find Simon's age and Marcie's age.</em>

<em />

Let Simon's age be x and Marcie's age be y

<u>Simon is 3 years more than 4 times marcie, so we can write:</u>

x = 4y + 3

Also,

<u>Sum of their ages is 58, so we can write:</u>

x + y = 58

or x = 58 - y

Now, we substitute this into 1st equation and solve for y first:

x = 4y + 3\\58-y = 4y + 3\\58-3=4y+y\\55=5y\\y=\frac{55}{5}\\y=11

We know

x = 58 - y

so,

x = 58 - 11

x = 47

So,

Simon's Age = 47

Marcie's Age = 11

3 0
3 years ago
What is the value of x in the equation -6/7= -×/84?
pantera1 [17]
-6/7 = -x/84

84/7 = 12

12(-6) = -72

x = -72

So, -6/7 = -72/84 because -72/84 simplifies to -6/7

4 0
3 years ago
Read 2 more answers
Does the given ordered pair, (-3,5/2) satisfies the given equation. 5x-2y=5 ?
anzhelika [568]

Answer:

No, it does not.

5 0
3 years ago
!!!URGENT!!!
GenaCL600 [577]

Answer:

r = 0.

Step-by-step explanation:

The slope = (y2 - y1) / (x2 - x1)

So  (r - (-3)) / (-4-2) = -1/2

(r + 3) / -6 = -1/2

2(r + 3)  = 6

2r + 6 = 6

2r = 6 - 6 = 0

r = 0  (answer).

7 0
4 years ago
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