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Vsevolod [243]
3 years ago
5

Can someone message me I need help ASAP by tmr

Mathematics
1 answer:
lakkis [162]3 years ago
3 0
I can also help :)))
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Please helpp 10 points and brainlyist if you are right.Thanks
Annette [7]

Answer:

58

Step-by-step explanation:

8 0
3 years ago
Answers ASAP simplify the ratio answer both questions
ruslelena [56]

Answer:

The answers are 40 : 1 and 16 : 5

Step-by-step explanation:

3. ) 400 : 10

Cancel out two of the zeros to get-

40 : 1

6. ) 1600m : 5km

1 km = 100 m, Therefore-

1600 : 500

Cancel out the zeros to get-

16 : 5

4 0
3 years ago
JK is tangent to a circle with centre H as shown below. What is HK ?<br> 8 mi<br> 15 mi
sashaice [31]

Given:

JK is tangent to a circle with center H

To find:

The length of HK.

Solution:

The image is attached below.

JK = 8 mi, HJ = 15 mi

JK is tangent to a circle.

The tangent is always perpendicular to the radius.

Therefore, m∠J = 90°

Using Pythagoras theorem:

HK² = JK² + HJ²

HK² = 8² + 15²

HK² = 64 + 225

HK² = 289

HK² = 17²

Taking square root on both sides.

HK = 17

The length of HK is 17 mi.

3 0
3 years ago
Carrie gave her hair stylist a $4.20 tip. The tip was 15% of the cost of the
Wittaler [7]

The total cost of her haircut was 28 dollars

step by step:

(percentage) 15 x 6 = 90

4.20 x 6 =25.2

(perscentage) 15 divided by 3 = 5

4.20 divided by 3 = 1.4

1.4 + 1.4 = 2.8

25.2 + 2.8 =28

4 0
3 years ago
The boiling point of jet fuel is 329°
natka813 [3]

Since, the boiling point of jet fuel  = 329 °F

We have to convert the boiling point of jet fuel in ^\circ C.

The expression which is used to convert ^\circ F to ^\circ C is given by:

C = \frac{5}{9}(F-32)

= \frac{5}{9}(329-32)

= \frac{5}{9}(297)

= 165^\circ C

Therefore, the boiling point of jet fuel is 165 ^\circ C.

8 0
3 years ago
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