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3 years ago

What is the point on a graph at which the graph crosses thd y-axis

Mathematics

2 answers:

Wewaii [24]3 years ago

8 0

Answer:

y intercept

Step-by-step explanation:

The [y-intercept] is the point where the line crosses the y-axis. Notice that the y-intercept occurs where x = 0, and the x-intercept occurs where y = 0.

Aloiza [94]3 years ago

5 0

Answer:

Y-intercept

Step-by-step explanation:

That is another name for it

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FIND THE AREA (LEAVE EXPLANATION)

VladimirAG [237]

Answer:

20 yd²

Step-by-step explanation:

lets do the big one

4 x (6-2) = 4 x 4 = 16 yd²

2 x (4-2) = 2x2 = 4 yd²

16 yd² + 4 yd² = 20 yd²

Another way

Find the area of the figure if it was a rectangle

4 x 6 = 24 yd²

then subtract 2 x 2 = 24 yd² - 4 yd² = 20 yd²

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3 years ago

Read 2 more answers

A parallelogram has a base of 9 km and a height of 5 km.

Luba_88 [7]

Answer:

Area= b*h

9*5=45km^2

Step-by-step explanation:

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3 years ago

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taurus [48]

Answer:

Step-by-step explanation‎:

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3 years ago

Expand.<br> Your answer should be a polynomial in standard form.<br> (3c + 2)(c^2-6c-4)

evablogger [386]

Answer:

After expanding the polynomial $(3c + 2)(c^2-6c-4)$ we get $3c^3-16c^2-24c-8$

Step-by-step explanation:

We need to expand the polynomial $(3c + 2)(c^2-6c-4)$

Multiply the terms:

$(3c + 2)(c^2-6c-4)\\=3c(c^2-6c-4)+2(c^2-6c-4)\\=3c^3-18c^2-12c+2c^2-12c-8\\=3c^3-18c^2+2c^2-12c-12c-8\\=3c^3-16c^2-24c-8$

So, after expanding the polynomial $(3c + 2)(c^2-6c-4)$ we get $3c^3-16c^2-24c-8$

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3 years ago

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Iteru [2.4K]

Answer:

Step-by-step explanation:

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3 years ago