Answer:
The required probability (P) = 1/6
Step-by-step explanation:
From the given information:
Suppose two dice are observed; Then the number of outcomes in first dice = 6 i.e (1,2,3,4,5,6) and also the number of outcomes in second dice = 6 as well i.e (1,2,3,4,5,6)
The total number of outcomes of two dices = 6×6 = 36
Now for a sum that is less than 5; their outcomes are [(1,1) ,(1,2) , (1,3) ], [(2,1), (2,2) ], (3,1) = 6 outomes
The total number of outcomes for the sum that is less than 5 = 6
∴
The required probability (P) = Total number of outcomes for the sum that is less than 5 / Total number of outcomes of two dices
The required probability (P) = 6/36
The required probability (P) = 1/6
