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tensa zangetsu [6.8K]
3 years ago
15

How do I fine the perimeter of these triangles?

Mathematics
1 answer:
arsen [322]3 years ago
3 0

constant of proportionality => COP

3: P(triangle ABC) = 84

COP = 18/15 = 1.2

Since you are finding the larger triangle, multiply the other numbers by 1.2

25 * 1.2 = 30

28 * 1.2 = 33.6

17 * 1.2 = 20.4

add them all up (answer up top)

5: P(triangle ABC) = 61.2

COP = 9/5 = 1.8

Since you are finding the larger triangle, multiply the other numbers by 1.8

9 * 1.8 = 16.2

13 * 1.8 = 23.4

12 * 1.8 = 21.6

add them all up (answer up top)

6: P(triangle RST) = 110

RP and PT are congruent, this means that PT is also 20

COP = 40/20 = 2

Since you are finding the larger triangle, multiply the other numbers by 2

25 * 2 = 50

20 * 2 = 40

10 * 2 = 20

add them all up (answer up top)

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Answer: Choice A) M = 0.25n + 100

=============================================================

Explanation:

For now, I'll treat n as x, and M as y.

In other words,

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Let's select two points from this graph. I'll pick (200,150) and (400,200)

The slope of the line through those points is

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m = (200-150)/(400-200)

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Now we'll use the point (x,y) = (200,150) along with that slope value to find the y intercept b

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You could also use (x,y) = (400,200) and you should get the same b value.

In fact, any other point from this graph works as well.

------------------------------

Since m = 0.25 and b = 100, we go from y = mx+b to y = 0.25x+100

This then translates over to M = 0.25n + 100 which is choice A

To help verify this, let's say we plugged in n = 100

M = 0.25*n + 100

M = 0.25*100 + 100

M = 25 + 100

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Which is confirmed by what the graph shows. I'll let you check the other points as well.

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