The distacne between the points (x1,y1) and (x2,y2) is

so the distance between (4,5) and (10,13) is
well, first
x1=4
y1=5
x2=10
y2=13
so



D=√100
D=10
the distance is 10 units
(2, 6)
x = 2
y = 6
y - x > -3
6 - 2 > -3
4 > -3
Therefore the answer is (2, 6)
The LCD = 6x^2y^3 ( because LCD of 3 and 6 = 6, LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)
now divide 3x^2y into the LCD then multiply this by 5 to get the first term in the numerator and do similar process to get second term, so we get:-
5(2y^2) - 4(x)
------------------
6x^2y^3
= 2( 5y^2 - 2x)
-----------------
6x^2y^3
= 5y^2 - 2x
-----------
3x^2y^3