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Lady bird [3.3K]
3 years ago
8

15 lb 7 oz - 6 lb 8 oz

Mathematics
1 answer:
mixas84 [53]3 years ago
6 0

Answer: 8.5lbs 7 oz

Step-by-step explanation:

8oz=.5lbs

15lbs 7oz-6.5lbs=

8.5lbs 7 oz

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Stock worth $80 a share dropped in value by 15% on Tuesday, then increased by $7 the next Wednesday and, finally, increased by 1
Nutka1998 [239]
<h2>Steps</h2>

So here are a couple expressions when a value changes by percentage (p = percentage in decimal form and m = original value):

  • When <em>decrease</em>: (1 - p)m
  • When <em>increase</em>: (1 + p)m

So firstly, the $80 share dropped by 15%. Since this is a <em>decrease</em>, follow the appropriate expression:

15\%=0.15\\\\(1-0.15)*80\\0.85*80\\68

<em>On Tuesday, the share went from $80 to $68</em>

Next, on Wednesday the share increased by $7. With this, just add $68 and 7.

68+7=75

<em>On Wednesday, the share went from $68 to $75</em>

Lastly, on Thursday the share increased by 12%. Since this is an <em>increase</em>, follow the appropriate expression:

12\%=0.12\\\\(1+0.12)*75\\1.12*75\\84

<h2>Answer</h2>

<u>The final price of the share is $84.</u>

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Answer:

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Step-by-step explanation:

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On a piece of paper, graph f(x) = 4 x (0.5)^x
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The complete question is

"On a piece of paper, graph f(x) = 4. (0.5)^x Then determine which answer choice matches the graph you drew."

The given function is an exponential function. The graph of option C is the correct answer.

<h3>What are exponential functions?</h3>

When the expression of function is such that it involves the input to be present as an exponent (power) of some constant, then such function is called exponential function.

There usual form is specified below. They are written in several such equivalent forms.

For example, y^x

, where a is a constant is an exponential function.

The function is given as

f(x) = 4. (0.5)^x

AS we can see that the given function is an exponential function.

Thus, the graph of option C is the correct answer.

Learn more about exponential here:

brainly.com/question/2193820

#SPJ1

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