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NNADVOKAT [17]
3 years ago
10

you can see that there is 8 cm in middle of the trapezoid. above the trapezoid, it says 6 cm, below the trapezoid, it says 11 cm

. find the area of the trapezoid and answer this question in square cm.​

Mathematics
1 answer:
cestrela7 [59]3 years ago
8 0

Answer:

Step-by-step explanation:

The area of a trapezoid is the average of the parallel bases times the height or distance between the two bases

A=h(b1+b2)/2

Here we have h=8cm, b1=6cm, and b2=11cm so

A=8(6+11)/2

A=8(17)/2

A=4(17)

A=68 cm^2

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Y=2x+9 y=4x-9 Solve the system of equations.
Deffense [45]

Answer:

Your solution is (9, 27) or x = 9, y = 27

Step-by-step explanation:

y = 2x + 9

y = 4x - 9

We can see that both of these equations equal y, so we can set them equal to each other.

2x + 9 = 4x - 9

Add 9 to both sides.

2x + 18 = 4x

Subtract 2x from both sides.

18 = 2x

Divide both sides by 2.

9 = x

Now we want to find y. To do this, plug x = 9 back into one of the original equations.

y = 2(9) + 9

Multiply.

y = 18 + 9

Add.

y = 27

Your solution is (9, 27)

Check your answer by plugging x = 9 and y = 27 back into the original equations.

y = 2x + 9

27 = 2(9) + 9

27 = 18 + 9

27 = 27

y = 4x - 9

27 = 4(9) - 9

27 = 36 - 9

27 = 27

Your answer is correct.

Hope this helps!

3 0
3 years ago
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Which ordered pairs make the open sentence true?
Hitman42 [59]

Answer:

-2,1

Step-by-step explanation:

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8 0
3 years ago
5times5 =..:.::.please help
gtnhenbr [62]

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25 Lol

Step-by-step explanation:

5 0
2 years ago
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Write the fraction is simplest form.<br> 4) 7/28 <br> 5) 12/20
KATRIN_1 [288]

Answer:

1/4 and 3/5

Step-by-step explanation:

4. 7/28 5. 12/20

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8 0
3 years ago
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{20,1,6,10,11}<br> Find the subset and the proper subset.
liubo4ka [24]
With 5 elements in A={20,1,6,10,11}, there are 2^5=32 possible subsets, including
the null set, and A itself.
Any subset that is identical to A is NOT a proper subset.
Therefore there are 31 proper subsets, plus the subset {20,1,6,10,11}.

The subsets are:
null set  {} (has no elements) ........total 1
{20},{1},{6},{10},{11}.......................total 5
{20,1},{20,6}...{10,11}.....................total 10
{20,1,6},{20,1,10},...{6,10,11}.........total 10
{20,1,6,10}...{1,6,10,11}.................total 5
{20,1,6,10,11}.................................total 1
Altogether 32 subsets.


4 0
3 years ago
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