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Klio2033 [76]
3 years ago
8

You are working in a warehouse counting product on a pallet. If there are 15 3/4 items on the pallet and 2/5 of the product cont

ainers are defective, how many can be ready for sale?
Mathematics
1 answer:
Blizzard [7]3 years ago
6 0

Answer:

3

Step-by-step explanation:

because 5 divided by 15 is 3

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Calculate the probability of each of the following events. (a) {at most three lines are in use} .72 Correct: Your answer is corr
andre [41]

Answer:

(a) The Probability that at most three lines are in use is 0.70.

(b) The Probability that fewer than three lines are in use is 0.45.

(c) The Probability that at least three lines are in use is 0.55.

(d) The Probability that between two and five lines, inclusive, are in use is 0.70.

(e) The Probability that between two and four lines, inclusive, are not in use is 0.35.

(f) The Probability that at least four lines are not in use is 0.70.

Step-by-step explanation:

<u>The complete question is: </u>A mail-order company business has six telephone lines. Let X denote the number of lines in use at a specified time. Suppose the pmf of X is as given in the accompanying table.

X    0          1       2       3          4             5               6

P(X)  0.10      0.15      0.20       0.25         0.20      0.05         0.05  

Calculate the probability of each of the following events.

(a) {at most three lines are in use}

(b) {fewer than three lines are in use}  

(c) {at least three lines are in use}  

(d) {between two and five lines, inclusive, are in use}

(e) {between two and four lines, inclusive, are not in use}

(f) {at least four lines are not in use}

Now considering the above probability distribution;

(a) The Probability that at most three lines are in use is given by = P(X \leq 3)

    P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

                  = 0.10 + 0.15 + 0.20 + 0.25

                  = 0.70

(b) The Probability that fewer than three lines are in use is given by = P(X < 3)

    P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

                  = 0.10 + 0.15 + 0.20

                  = 0.45

(c) The Probability that at least three lines are in use is given by = P(X \geq 3)

    P(X \geq 3) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

                  = 0.25 + 0.20 + 0.05 + 0.05

                  = 0.55

(d) The Probability that between two and five lines, inclusive, are in use is given by = P(2 \leq X \leq 5)

    P(2 \leq X \leq 5) = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

                         = 0.20 + 0.25 + 0.20 + 0.05

                         = 0.70

(e) The Probability that between two and four lines, inclusive, are not in use is given by = 1 - P(2 \leq X \leq 4)

    1 - P(2 \leq X \leq 4) = 1 - [P(X = 2) + P(X = 3) + P(X = 4)]

                             = 1 - [0.20 + 0.25 + 0.20]

                             = 1 - 0.65 = 0.35

(f) The Probability that at least four lines are not in use is given by = 1 - Probability that at least four lines are in use = 1 - P(X \geq 4)

    1 - P(X \geq 4) = 1 - [P(X = 4) + P(X = 5) + P(X = 6)]

                       = 1 - [0.20 + 0.05 + 0.05]

                       = 1 - 0.30 = 0.70

5 0
3 years ago
36 ft 41 1/2 ft find the area
Likurg_2 [28]
36*41.5=1494
1494 is the area


4 0
3 years ago
Virginia tossed a coin and it landed heads up three times in a row. What is the probability that this same coin will land heads
Savatey [412]
0 times is the answer
6 0
3 years ago
Which graph shows y &lt; x2 + 1?<br> c.
MAVERICK [17]

Answer:

Its minecraft duh

Step-by-step explanation:

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8 0
3 years ago
Two trains leave Raleigh at the same time one traveling north and the other south the first train travels at 50 miles per hour a
Elis [28]

Answer:

<h2>2.5 hours</h2>

Step-by-step explanation:

Step one:

given data

for train one

speed= 50miles per hour

for train two

speed= 60miles per hour

the total distance between both trains=275miles

Step two:

the expression for speed= distance/time

so that, distance= speed*time

let the time be t

we are going to combine both distances

train one distance =50t

train two distance =60t

Hence total distance

50t+60t=275

110t=1=275

t=275/110

t=2.5 hours

<u>It will take 2.5 hours</u>

4 0
2 years ago
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