Answer:
h= (V/πr²)(3)
Step-by-step explanation:
The first 3 are examples of the difference of 2 squares so you use the identity
a^2 - b^2 = (a + b)(a - b)
x^2 - 49 = 0
so (x + 7)(x - 7) = 0
so either x + 7 = 0 or x - 7 = 0
giving x = -7 and 7.
Number 7 reduces to 3x^2 =12, x^2 = 4 so x = +/- 2
Number 8 take out GCf (d) to give
d(d - 2) = 0 so d = 0 , 2
9 and 10 are more difficult to factor
you use the 'ac' method Google it to get more details
2x^2 - 5x + 2
multiply first coefficient by the constant at the end
that is 2 * 2 = 4
Now we want 2 numbers which when multiplied give + 4 and when added give - 5:- -1 and -4 seem promising so we write the equation as:-
2x^2 - 4x - x + 2 = 0
now factor by grouping
2x(x - 2) - 1(x - 2) = 0
(x - 2) is common so
(2x - 1)(x - 2) = 0
and 2x - 1 = 0 or x - 2 = 0 and now you can find x.
The last example is solved in the same way.
The answer is zero
Hopes this helps :)
Answer:
y = 5
Step-by-step explanation:
Step 1: Write equation
-(4y + 2) - (-3y - 6) = -1
Step 2: Solve for <em>y</em>
- Distribute: -4y - 2 + 3y + 6 = -1
- Combine like terms: -y + 4 = -1
- Subtract 4 on both sides: -y = -5
- Divide both sides by -1: y = 5
Step 3: Check
<em>Plug in y to verify it's a solution.</em>
-(4(5) + 2) - (-3(5) - 6) = -1
-(20 + 2) - (-15 - 6) = -1
-22 - (-21) = -1
-22 + 21 = -1
-1 = -1
Answer:
circumference is 21.99 and area is 47 and 2/35 unit squared sorry if its a little late
