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2 years ago

Mary mixes 11/12 oz of red paint with 1 3/4 oz of white paint.

Mathematics

1 answer:

Doss [256]2 years ago

8 0

Im assuming that to be the case, so:-

11/12 + 1 3/4

= 11/12 + 7/4

= 11/2 + 21 / 12

= 32 / 12

= 2 2/3 OZ. (Choice D).

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Please help me and explain thank you so much I appreciate it

andreev551 [17]

Answer:

He gets 32, $10 bills.

Step-by-step explanation:

He puts in $630.

3 times $50 equals $150.

8 times $20 equals $160.

$150 plus $160 equals $310.

$630 minus $310 equals $320.

$320 divided by 10 equals 32.

So he gets 32, $10 bills.

8 0

2 years ago

Solve for z.<br><br> 3 + 9z = –7 + 10z<br><br> z =

stiv31 [10]

The answer should be z = 10

6 0

2 years ago

Read 2 more answers

( – 1, – 5) 7x+2y=13, 4x+4y=14

serious [3.7K]

Answer:

{x,y} = {6/5,23/10}

Step-by-step explanation:

[1] 7x + 2y = 13

[2] 4x + 4y = 14 <---------- linear equations given

Graphic Representation of the Equations : PICTURE
2y + 7x = 13 4y + 4x = 14

Solve by Substitution :

// Solve equation [2] for the variable y

[2] 4y = -4x + 14

[2] y = -x + 7/2

// Plug this in for variable y in equation [1]

[1] 7x + 2•(-x +7/2) = 13

[1] 5x = 6

// Solve equation [1] for the variable x

[1] 5x = 6

[1] x = 6/5

// By now we know this much :

x = 6/5

y = -x+7/2

// Use the x value to solve for y

y = -(6/5)+7/2 = 23/10

// Plug this in for variable y in equation [1]

[1] 7x + 2•(-x +7/2) = 13

[1] 5x = 6

// Solve equation [1] for the variable x

[1] 5x = 6

[1] x = 6/5

// By now we know this much :

x = 6/5

y = -x+7/2

// Use the x value to solve for y

y = -(6/5)+7/2 = 23/10

4 0

1 year ago

A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken

mihalych1998 [28]

Answer:

n=6147

Step-by-step explanation:

1) Notation and definitions

$X=1$ number of citrus trees that are infected with the citrus red mite.

$n=5$ random sample taken

$\hat p=\frac{1}{5}=0.2$ estimated proportion of citrus trees that are infected with the citrus red mite.

$p$ true population proportion of citrus trees that are infected with the citrus red mite.

Me=0.01 represent the margin of error desired

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical values we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical values would be given by: