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3 years ago

Can you help me with this? I don't seem to understand..

Mathematics

1 answer:

gulaghasi [49]3 years ago

3 0

All you have to do is set up 2 proportions, where one paint you know and the other you do not know and make it equal to the ratio as 2 blue : 5 yellow

For example: 1 blue/x yellow = 2 blue/5 yellow, and then cross multiply and solve for x.

Do this for all unknowns, blue and yellow paint making it equal to the ratio and solve for the unknown.

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Determine for which values of m the function variant Φ(x) = x^m is a solution to the given equation. a. 3x^2 (d^2y/dx^2) + 11x(d

miv72 [106K]

Answer:

a) m = -9 or m = 1

b) m = 1 + √6 or m = 1 -√6

Step-by-step explanation:

for

Φ(x) = x^m

then

dΦ/dx (x) = m*x^(m-1)

d²Φ/dx² (x) = m*(m-1)*x^(m-2)

then

for a

3x^2 (d^2y/dx^2) + 11x(dy/dx) - 3y = 0

3x^2*m*(m-1)*x^(m-2) + 11*x* m*x^(m-1) - 3*x^m = 0

3*m*(m-1)*x^m + 11*m*x^m- 3*x^m = 0

dividing by x^m

3*m*(m-1) + 11*m - 3 =0

3*m² + 8 m - 3 =0

m= [-8 ± √(64 + 4*3*3)]/2 = (-8±10)/2

m₁ = -9 , m₂= 1

then Φ(x) = x^m is a solution for the equation a , when m = -9 or m = 1

for b)

x^2 (d^2y/dx^2) - x(dy/dx) - 5y = 0

x^2*m*(m-1)*x^(m-2) - x* m*x^(m-1) - 5*x^m = 0

m*(m-1)*x^m -m *x^m- 5*x^m = 0

dividing by x^m

m*(m-1) -m - 5 =0

m² - 2 m - 5 =0

m= [2 ± √(4 + 4*1*5)]/2 = (2±√24)/2 = 1 ±√6

m₁ = 1 + √6 , m₂ = 1 - √6

then Φ(x) = x^m is a solution for the equation b , when m = 1 + √6 or m = 1 - √6

7 0

2 years ago

Read 2 more answers

Suppose cotangent (theta) = startfraction 5 over 12 endfraction, where pi less-than theta less-than startfraction 3 pi over 2 en

Nimfa-mama [501]

sin(Q) = -(12/13)

<h2>What are trigonometric ratios?</h2>

Trigonometric ratios are the ratios of the length of sides of a triangle. These ratios in trigonometry relate the ratio of sides of a right triangle to the respective angle. The basic trigonometric ratios are sin, cos, and tan, namely sine, cosine, and tangent ratios. The other important trig ratios, cosec, sec, and cot, can be derived using the sin, cos, and tan respectively. It is a branch of mathematics that deals with the relation between the angles and sides of a right-angled triangle.

cot(Q) = 5/12

sin(Q) = 1/cosec(Q)

$sin(Q) = \frac{1}{\sqrt{1+{cot}^2(Q)}}\\sin(Q) = \frac{1}{\sqrt{1+\frac{25}{144}}}\\sin(Q) = \frac{1}{\sqrt{\frac{169}{144}}}\\$

sin(Q) = ±12/13

Because, π < Q < (3/2)π

Therefore, sin(Q) = -12/13

To learn more, Visit:

brainly.com/question/17895477

#SPJ4

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1 year ago

A recursive rule for an arithmetic sequence is a1=−3;an=an-1+7

charle [14.2K]

C is the answer. Hope you get a good grade

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3 years ago

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I put $500 in a saving account that warns 7% interest compounded quarterly. How much will be in the account after 1 year? Rounde

Fantom [35]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$500\\
r=rate\to 7\%\to \frac{7}{100}\to &0.07\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &1
\end{cases}
\\\\\\
A=500\left(1+\frac{0.07}{4}\right)^{4\cdot 1}\implies A=500(1.0175)^4\implies A\approx 535.92951564$

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3 years ago

What is the image point of ( -5,0 ) after a translated left 2 units and down 3 units ?

kvv77 [185]

Answer: ( -7 , -3 )

Step by step:
The point: ( X , Y )
Left 2 units = change X by -2
So, -5 subtract by 2 equals -7
Down 3 units = change Y by -3
So, 0 subtract by 3 equals -3
Now, X = -7 and Y = -3, so the answer is ( -7 , -3 )

Hope this helps! Please tell me if I did anything wrong, thank you!

5 0

3 years ago