Answer:
0.30
Step-by-step explanation:
Probability of stopping at first signal = 0.36 ;
P(stop 1) = P(x) = 0.36
Probability of stopping at second signal = 0.54;
P(stop 2) = P(y) = 0.54
Probability of stopping at atleast one of the two signals:
P(x U y) = 0.6
Stopping at both signals :
P(xny) = p(x) + p(y) - p(xUy)
P(xny) = 0.36 + 0.54 - 0.6
P(xny) = 0.3
Stopping at x but not y
P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06
Stopping at y but not x
P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24
Probability of stopping at exactly 1 signal :
P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30
Answer:
The 3rd answer i think
Step-by-step explanation:
Answer:
6a
Step-by-step explanation:
A coefficient is the number hooked to the variable therefore the term 6a is your coefficient
The answer is 0. While the answer for n is approximately 2.384503, there are no EXTRANEOUS solutions. Again, the answer is a.) 0
A = w(2w + 3)
90 = 2w^2 + 3w
2w^2 +3w - 90 = 0
(w-6)(2w+15) = 0 (TRINOMIAL FACTORING)
w = 6 inch ( it can't be -15/2 because lengths can't be negative)
l = 2w + 3
= 15 inch
