Answer:
1 or 5
Step-by-step explanation:
Given the function h(x)=(2x−2)(x−5)
The zeros of h(x) are the values of x for which h(x)=0
h(x)=(2x−2)(x−5)=0
Note that if a.b=0, either a=0 or b=0.
Appying the above,
If (2x−2)(x−5)=0
Then:
2x−2=0 or x-5=0
2x=2 or x=5
x=1 0r 5
The zeroes of h(x) as defined are 1 or 5.
1 , 5
5
7
15
i think this is right
It’s 0.09 or .09. Hope this helps:)
Answer:
8
Step-by-step explanation:
To find range, subtract the lowest number(1) from the highest number(9)
highest-lowest
9-1
8
So, the range is 8
Hope this helps! :)
