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zalisa [80]
3 years ago
15

Could Someone PLEASE help me with this it is stumping me.

Mathematics
1 answer:
Bess [88]3 years ago
4 0

9514 1404 393

Answer:

  G  45

Step-by-step explanation:

If Z is the circumcenter, it is equidistant from the vertices T, U, V. That is, ΔZUV is an isosceles triangle and Y is the midpoint of UV.

If Y is the midpoint of UV, then UY = VY = 22.5, and UV = UY +VY = 45.

The length of UV is 45.

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My brain small so could you plz anwser his 6/11+ 2/ 3
Lena [83]

Answer:

1 7/33

Step-by-step explanation:

6/11 + 2/3 --> We need a common denominator

--> 11 x 3 = 33

33 is our common denominator

6 x 3 = 18

2 x 11 = 22

18/33 + 22/33 = 40/33

Convert to a mixed number

=> 1 7/33

Thus, we have our answer.

4 0
4 years ago
What is 9/10 of 30 pls help
Bingel [31]
27, just multiply30 by 9/10
6 0
3 years ago
Andy's weight is 5 kilograms less than twice his brother's. Together they weigh 100 kilograms. What are their weights?
lakkis [162]

Answer:

Step-by-step explanation:

Let x be the brother's weight.

Then 2x-5 is Andy's weight.

x+(2x-5)=100

3x-5=100

3x=105

4 0
3 years ago
What is the slope of the line on the graph below?
Mrac [35]
I believe the slope of the line is 1/3
5 0
3 years ago
The problem of matching aircraft to passenger demand on each flight leg is called the flight assignment problem in the airline i
Darina [25.2K]

Answer:

Step-by-step explanation:

Given that the demand for the 6 p.m. flight from Toledo Express Airport to Chicago's O'Hare Airport on Cheapfare Airlines is normally distributed with a mean of 132 passengers and a standard deviation of 42

Let X be the no of passengers who report

X is N(132, 42)

Or Z is \frac{x-132}{42}

a) Suppose a Boeing 757 with a capacity of 183 passengers is assigned to this flight.

the probability that the demand will exceed the capacity of this airplane

=P(X>183) = P(Z>1.21) =

=0.5-0.3869\\=0.1131

b)  the probability that the demand for this flight will be at least 80 passengers but no more than 200 passengers

=P(80\leq x\leq 200)\\= P(-1.23\leq z\leq 1.62)\\

=0.4474+0.3907

=0.8381

c) the probability that the demand for this flight will be less than 100 passengers

=P(x

d) If Cheapfare Airlines wants to limit the probability that this flight is overbooked to 3%, how much capacity should the airplane that is used for this flight have? passengers

=P(Z>c)=0.03\\c=1.88\\X=132+1.88(42)\\=210.96

e) 79th percentile of this distribution

=132+0.81(42)\\= 166.02

7 0
4 years ago
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