The answer is approximately 11.18.
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Answer:
a = 3, b = -8
Step-by-step explanation:
Solving the first equation for y, we get ...
2y +16 = 6x . . . . . given
y = 8 +3x . . . . . . . divide by 2
y = 3x -8 . . . . . . . subtract 8
In order for the system of equations to have infinitely many solutions, the second equation must be the same as this:
y = ax +b
a = 3, b = -8
Answer:
Step-by-step explanation:
Let x represent the number of 3-lb bags purchased. Then the total purchase was ...
$2(8 -x) +$5.50(x) = $37
16 +3.50x = 37 . . . . . . . . . divide by $, collect terms
3.50x = 21 . . . . . . . . . . . . . subtract 16
21/3.50 = x = 6 . . . . . . . . divide by the coefficient of x
You bought 6 3-lb bags of peanuts and 2 1-lb bags.
Answer:
f(x) > 0 over the interval 
Step-by-step explanation:
If f(x) is a continuous function, and that all the critical points of behavior change are described by the given information, then we can say that the function crossed the x axis to reach a minimum value of -12 at the point x=-2.5, then as x increases it ascends to a maximum value of -3 for x = 0 (which is also its y-axis crossing) and therefore probably a local maximum.
Then the function was above the x axis (larger than zero) from 
, until it crossed the x axis (becoming then negative) at the point x = -4. So the function was positive (larger than zero) in such interval.
There is no such type of unique assertion regarding the positive or negative value of the function when one extends the interval from to -3, since between the values -4 and -3 the function adopts negative values.
