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3 years ago

Please helppppppppppppppp

Mathematics

1 answer:

saveliy_v [14]3 years ago

5 0

Answer:

It's the 2nd one

Step-by-step explanation

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Solve each equation 3x^2=80

Lapatulllka [165]

Answer:

$x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}$

$x = \frac{\pm4\sqrt{15}}{3}$

Step-by-step explanation:

Hello!

Use the quadratic formula: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

First, let's convert our equation to standard form of a Quadratic: ax² + bx + c = 0

3x² = 80

3x² - 80 = 0

Note, thats the value of b will be 0, as there is no "bx"

Now, solve:

$x = \frac{-(0) \pm \sqrt{(0)^2 - 4(3)(-80)}}{2(3)}$ Plug in values
$x = \frac{\pm\sqrt{960}}{6}$ Simplify the radical (Discriminant)
$x = \frac{\pm8\sqrt{15}}{6}$ Pull out perfect squares
$x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}$ Reduce factors

The solutions are $x = \frac{4\sqrt{15}}{3}, x = \frac{-4\sqrt{15}}{3}$

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2 years ago

A line passes through the point (-9, -3) and has a slope of 2.

tresset_1 [31]

Answer:

Step-by-step explanation:

hello :

note :

Use the point-slope formula.

y - y_1 = m(x - x_1) when : x_1= -9 y_1= -3

m= 2 (the slope)

an equation in the point-slope form is : y +3 = 2(x+9)

means : y+3 =2x +18

an equation in slope-intercept id : y=2x+15

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2 years ago

Use the graph of the function to find its domain and range. Write the domain and range in interval notation

Daniel [21]

Answer:

Step-by-step explanation:

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2 years ago

What value of p makes the equation true?<br><br> -3p + 1/8 = - 1/4

allochka39001 [22]

Answer:

Step-by-step explanation:

i hope u understand !0k ?????

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3 years ago

Read 2 more answers

Help me pleasseeeee!!! its about algebraic properties of limits!

s2008m [1.1K]

$\text{Hello there! :)}$

$3. \sqrt{2} \\\\\text{4. 0}\\\\\text{5. dne}$

$\text{To find the overall limit, they must approach the same y-value from each side:}$

$\\\\3. \lim_{x \to \frac{\pi }{4} } 2sinx ={\sqrt{2}$

$\text{Therefore:}\\\\3. \lim_{x \to \frac{\pi }{4} } f(x)= {\sqrt{2} }$

$\text{For this question, evaluate the limit from the RIGHT-HAND side:}\\\\4. \lim_{x \to \pi +} f(x)\\\\ \text{Use the equation tanx to evaluate since it involves values greater than \pi:}\\\\$

$\lim_{x \to \pi +} tanx = 0\\\\\text{So:}\\\\ \lim_{x \to \pi +} f(x) = 0$

$5. \\\\\text{Evaluate the overall limit. Make sure both sides approach the same y=value:}\\\\ \lim_{x \to \pi } 2cosx= -2\\\\ \lim_{x \to \pi } tanx = 0\\\\ \text{ Therefore:}\\ \lim_{x \to \pi } f(x) = dne \text{ (Does not exist})$

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3 years ago