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iogann1982 [59]
3 years ago
10

» The perimeter of a rhombus of side d cm

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0

Given:

The perimeter of a rhombus of side d cm  is

p=4d

To find:

The perimeter of a rhombus of  side 3.2 cm.

Find the length of a side of a rhombus  of perimeter 14 cm.

Solution:

Side of a rhombus is 3.2 cm. So, its perimeter is

p=4(3.2)

p=12.8

Therefore, the perimeter of a rhombus of  side 3.2 cm is 12.8 cm.

The perimeter of another rhombus is 14 cm, and we need find its side.

p=4d

14=4d

Divide both sides by 4.

\dfrac{14}{4}=d

3.5=d

Therefore, the length of a side of a rhombus  of perimeter 14 cm is 3.5 cm.

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The length of a rectangle is 3131 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
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We have a rectangle with a diagonal included. That means we have to use Pythagorean's Theorem to find the missing dimensions. We start with the width as w. The length is 31 more than twice the width, so the length is 2w+31. The hypotenuse (diagonal) is 2 more than the length, so the diagonal measures 2w+33. In a right triangle, the hypotenuse is always the longest side, so we set up Pythagorean's Theorem using the bolded values as such: (2w+33)^2=w^2+(2w+31)^2. Distributing by multiplying we simplify to 4w^2+132w+1089=w^2+4w^2+124w+961. We need to solve for w. Once we do that we can use that value to find the length. What's nice is that the 4w^2 terms cancel each other out. So when we combine like terms and get them all on one side of the equals sign to factor we have w^2-8w-128=0. The 2 numbers that add up to -8 and multiply to -128 are 16 and -8. So the width is either 16 inches or the width is -8 inches. The 2 things in math that will never EVER be negative are time and distance/length. So -8 is out. The width is 16 inches. That means that the length is 2(16)+31, which is 63 inches. There you go!

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