Answer:
C
Step-by-step explanation:
Dividend policy (hypothesis) of firms as stated by Musa (2009) is a cultural phenomenon that changes continuously according to environment and time, hence it is necessary to continuously modify dividend behavioural models to capture those factors that are peculiar to a particular period and environment, as well as changes in tax.
Hope this helps
Answer:
- Josh's book lands first
- Ben's lands about 0.648 seconds later
Step-by-step explanation:
Using the given equation for v=60 and s=40, the height of Ben's book is ...
h(t) = -16t² +60t +40
We want to find t when h(t) = 0, so we're looking for the solution to ....
0 = -16t² +60t +40
Using the quadratic formula, we find the positive value of t to be ...
t = (-60 -√(60² -4(-16)(40)))/(2(-16)) = (15 +√385)/8 ≈ 4.3277
__
Similarly, the height of Josh's book is ...
0 = -16t² +48t +40
t = (-48 -√(48² -4(-16)(40)))/(2(-16)) = (12 +√304)/8 ≈ 3.6794
__
The time before Josh's book lands is shorter by ...
4.3277 -3.6794 ≈ 0.6482 . . . . . seconds
Josh's book reaches the ground first, by about 0.648 seconds.
Answer:
Total surface area : 733
The shape of the base is a rectangle with sides 11 in. and 12 in.
Step-by-step explanation:
The shape of the base is a rectangle with sides 11 in. and 12 in.
The surface area is the sum of the areas of the 5 sides.
Area of the base = 11*12 = 132
Area of the two triangles = (11*16)/2 = 88
Area of the back rectangle = 192
The theorem of Pitagora to find the oblique side: square root of (11*11 + 16*16)= 19.42 in.
So the area of the oblique face: 19.42* 12 = 233 (almost :) )
So total surface area: 132 + 88*2+192+233= 733 square in
Answer:
The Answer is gonna be D. 2
This is the right Answer:3
I hope you are having a great day ❤️❤️❤️
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete. I will assume the function is:

Required
Determine the rate of decay
In an exponential function
,
The decay rate of the function is calculated as:

By comparison:

So, the equation becomes:

Make r the subject


<em>The rate of decay is 0.14</em>