Answer:
4' x 2' x 1'
Step-by-step explanation:
Collins' cube has a volume of that is the length of any side, x, cubed: Vol = x^3. Since his box has 8^3, we can say that x = 2. <u>[2^3 = 8]</u>
Amil's box has one side that is 2x. That side would be 2*2 = 4 feet. His volume is also 8 ft^3. Amil's box also has a volume of 8 ft^3.
His box dimensions are therefore: (4)(X)(Y) = 8 ft^3 , where X and Y are whole-number dimensions for the other 2 dimensions of his box.
(4)(X)(Y) = 8 ft^3
X*Y = 2
The only combination of whole numbers for which this this would work is 1 and 2.
Amil's box is 4' x 2' x 1' or 8 ft^3
First,we need to understand the point-slope form:
Where x and y are the coordinates and m is the slope.
Put the above information into the equation:
y-(-6)=-3/4(x-2)
y+6 = -3/4 (x-2)
Therefore the answer is C.y+6 = -3/4 (x-2).
Hope it helps!
Just do 10.5 × 50 and whatever answer you get label as grams
Answer:
There are infinite solutions of x such as 0,1,2 ...
i.e for all x≥0 given inequality is true.
i.e x€[0,∞)
Three hundred ninety six divided by twenty four = 16.5
