Answer:
B. 56°
Step-by-step explanation:
We are given that m∠R is 66° and m∠T is 122°.
We can apply the supplementary rule since ∠S and ∠T are a linear pair. So, we can use ∠T to find ∠S through 180° - 122° = 58°.
Now, we can use ∠R and ∠S to find ∠Q.
66° + 58° = 124°
180° - 124° = 56°
Answer:
x=-4
Step-by-step explanation:
(x+4) ^ (1/3) + (2x+8) ^ (1/3) = 0
Subtract (x+4) ^ (1/3) from each side
(x+4) ^ (1/3) - (x+4) ^ (1/3)+ (2x+8) ^ (1/3) = -(x+4) ^ (1/3)
(2x+8) ^ (1/3) = -(x+4) ^ (1/3)
Cube each side
(2x+8) ^ (1/3) ^3= -(x+4) ^ (1/3)^3
2x+8 = -(x+4)
Distribute the negative sign
2x+8 = -x -4
Add x to each side
2x+8 +x =-x+x-4
3x+8 = -4
Subtract 8 from each side
3x+8-8 =-4-8
3x =-12
Divide by 3
3x/3 = -12/3
x = -4
Answer:
since those 2 lines are parrelel that means the angles are the same so
8x+6=4x+38
minus 6
8x=4x+32
minus 4x
4x=32
divide by 4
x=8
Hope This Helps!!!
There are 5^5 students on the school and 5^2 students per class.
So, think:
1 class ----------- 5^2 students
x classes ---------- 5^5 students
Multiply:
1 . 5^5 = x . 5^2
So,
5^5 = x.5^2
x = 
x = 
x = 
x = 125
There are 125 classes.
