20 : 0.75 = 40 : 1.5 = 80 : 3
Answer: 5.5km
Step-by-step explanation:
The scale given 1 : 25 000 , and it was said that on the map , the distance between two railway stations is 22 cm , this means that the scale of the map is 1: 25000 cm.
The scale 1 : 25 000 means that each centimeters on the map represent 25 ,000 in real life ,therefore , to calculate the real distance between the two railway station , we have
25,000 X 22
= 550000 cm
To convert this to km
Recall that
1 km = 100,000 cm
Therefore we will divide the answer by 100,000 , that is
550000/100000
= 5.5 km
Therefore , the real distance between the two railway stations is 5.5km
Im pretty sure it is length times width :)
1 mi and 900 ft,1 mile = 5280 ft
Answer:
A. f(x) = x^2 + 4x + 3
D. f(x) = -2x^2 - 8x + 1
Step-by-step explanation:
The axis of symmetry is found by h = -b/2a where ax^2 +bx +c
A. f(x) = x^2 + 4x + 3
h = -4/2*1 = -2 x=-2
B. f(x) = x^2 - 4x - 5
h = - -4/2*1 = 4/2 =2 x=2 not -2
C. f(x) = x^2 + 6x + 2
h = -6/2*1 = -3/2 = x=-3/2 not -2
D. f(x) = -2x^2 - 8x + 1
h = - -8/2*-2 = 8/-4 =-2 x=-2
E. f(x) = -2x^2 + 8x - 2
h = - 8/2*-2 = -8/-4 =2 x=2 not -2
