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ra1l [238]
3 years ago
9

Find the constant of proportionality k. Then write an equation for the relationship between x and y

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
6 0

Question:

Find the constant of proportionality k. Then write an equation for the relationship between x and y

\begin{array}{ccccc}x & {2} & {4} & {6} & {8} \ \\ y & {10} & {20} & {30} & {40} \ \ \end{array}

Answer:

(a) k = 5

(b) y = 5x

Step-by-step explanation:

Given

\begin{array}{ccccc}x & {2} & {4} & {6} & {8} \ \\ y & {10} & {20} & {30} & {40} \ \ \end{array}

Solving (a): The constant of proportionality:

Pick any two corresponding x and y values

(x_1,y_1) = (2,10)

(x_2,y_2) = (6,30)

The constant of proportionality k is:

k = \frac{y_2 - y_1}{x_2 - x_1}

k = \frac{30-10}{6-2}

k = \frac{20}{4}

k = 5

Solving (b): The equation

In (a), we have:

(x_1,y_1) = (2,10)

k can also be expressed as:

k = \frac{y- y_1}{x- x_1}

Substitute values for x1, y1 and k

5 = \frac{y- 10}{x- 2}

Cross multiply:

y - 10 = 5(x - 2)

Open bracket

y - 10 = 5x - 10

Add 10 to both sides

y - 10 +10= 5x - 10+10

y = 5x

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