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UkoKoshka [18]
3 years ago
15

Becky wanted to figure out what type of work would work the best for growing beans see you watered one with Coca-Cola one with l

emonade and another one just with water after one week she measure how high they had a growth (IV) (DV) (CONTROL)
Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
8 0
IV: type of liquid used to water the plant (coca-cola, lemonade, water)
DV: height of growth
Control: time grown, same temperature and location
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giving the incomplete equation 2N2O5 (g) which set of products completes and balances the incomplete equarion
a_sh-v [17]

Answer:

The complete question is as follows

Given the incomplete equation: 2 N2O5(g) ==>  Which set of products completes and balances the incomplete equation?

A)2 N2(g) + 3 H2(g)

B)2 N2(g) + 2 O2(g)

C)4 NO2(g) + O2(g)

D)4 NO(g) + SO2(g)

The correct option is C) 4NO2(g) + O2(g)

Explanation:

Note that the products should be NO2 and O2 since the reactant is entirely made up of N and O. option A is not correct as hydrogen cannot emerge as a product in this reaction. Matter can never be created or be destroyed bu can only change in a chemical reaction. Option D is not also correct for the same reason.

Option B is not correct since it did not balance the number of atoms of O and N in the reactant side of the equation.

The option C) 4NO2(g) + O2(g) is therefore the right option since it balances both the elements and the number of atoms of the elements present.

7 0
3 years ago
When FeC13 is ignited in an atmosphere of pure oxygen, this reaction takes place. 4FeCl3(sJ 30lgJ ~ 2F~0 (sJ 6Cl2(gJ If 3.00 mol
oksano4ka [1.4K]

Answer : The reagent present in excess and remains unreacted is, O_2

Solution : Given,

Moles of FeCl_3 = 3.00 mole

Moles of O_2 = 2.00 mole

Excess reagent : It is defined as the reactants not completely used up in the reaction.

Limiting reagent : It is defined as the reactants completely used up in the reaction.

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

2FeCl_3(s)+O_2(g)\rightarrow 2FeO(s)+3Cl_2(g)

From the balanced reaction we conclude that

As, 2 moles of FeCl_3 react with 1 mole of O_2

So, 3.00 moles of FeCl_3 react with \frac{3.00}{2}=1.5 moles of O_2

From this we conclude that, O_2 is an excess reagent because the given moles are greater than the required moles and FeCl_3 is a limiting reagent and it limits the formation of product.

Hence, the reagent present in excess and remains unreacted is, O_2

4 0
3 years ago
The unfolding of a protein by heat or chemical treatment is referred to as
aksik [14]

Answer:

14

Explanation:

6 0
3 years ago
Read 2 more answers
Since all atoms have negatively charged electrons, shouldn’t every sample of matter have a negative charge ? Explain
Salsk061 [2.6K]

The three sub-atomic particles that made up an atom are electron, proton and neutron. The proton and neutron are present in the nucleus of an atom whereas electrons revolve around the nucleus in the orbits. The atoms are electrically neutral that is they have no charge due to the presence of equal number of protons (which is positively charged) and electrons (which is negatively charged).

All the atoms have negatively charged electrons which are counter balanced by the presence of equal number of protons in the nucleus of an atom and thus, the element is neutral in nature and possess no charge.

6 0
3 years ago
Balance the following chemical
poizon [28]

Answer:

Explanation:

A chemical formula can be defined as a notation that is used to show which element and how many is contained in a chemical compound.

Also, in chemistry, the sum of charges of the anion and the cation of any ionic compound is always equal to zero.

A chemical equation is considered to be balanced when the amount of reactants on the left is equal to the amount of products on the right.

Therefore;

[2]FeBr3 + [3]Na2S → [1]Fe2S3 + [6]NaBr

In the above chemical equation, we will balance the reactants in the chemical equation with the smallest coefficients possible;

2FeBr_{3} + 3Na_{3}S ----> Fe_{2}S{3} + 6NaBr

Two (2) moles of Iron (III) Bromide reacts with two (2) moles of Sodium Sulfide to form Iron (III) Sulfide and Sodium Bromide.

4 0
3 years ago
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