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Shkiper50 [21]
3 years ago
15

Oxygen and nitrogen are both gases at room temperature. Explain why oxygen has a greater force of attraction between its particl

es than nitrogen. (Room temperature is 20°C) please help
Chemistry
1 answer:
RideAnS [48]3 years ago
8 0

Answer:

Explanation:

Oxygen molecules and Nitrogen molecules forms in a very similar way. The attraction between particles of oxygen is great due to its very high electronegativity value. Oxygen has a higher electronegative value compared to nitrogen.

Electronegativity of an atom is the relative tendency with which atoms of an element attracts valence electrons in a chemical bond. Valence electrons are used in forming chemical bonds. They can be transferred from one atom to the other or they can be shared.

Oxygen is the second most electronegative atom on the periodic table. To form a bond, it shares the valence electrons in order for its octet to be complete. Pull for the valence electrons between the contributing atoms is very strong due to their large electronegative values. This pull is stronger compared to that between nitrogen atoms.

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A mixture of 14.0 grams of H2, 84.0 grams of N2, and 64.0 grams of O2 are placed in a flask. The partial pressure of the O2 is 7
Hitman42 [59]

Answer:

P_{tot}=465.27torr

Explanation:

Hello there!

In this case, according to the given information, it will be possible for us to use the Dalton's law, in order to solve this problem. However, we first need to calculate the mole fraction of oxygen by firstly calculating the moles of each gas:

n_{H_2}=\frac{14.0g}{2.02g/mol} =6.93mol\\\\n_{N_2}=\frac{84.0g}{28.02g/mol}=3.00mol\\\\n_{O_2}=\frac{64.0}{16.00g/mol}  =2.00mol

Next, we calculate such mole fraction as follows:

x_{O_2}=\frac{2}{6.93+3+2} =0.168

Then, given the following equation:

P_{O_2}=P_{tot}*x_{O_2}

So we solve for the total pressure as follows:

P_{tot}=\frac{P_{O_2}}{x_{O_2}} \\\\P_{tot}=\frac{78.00torr}{0.168} \\\\P_{tot}=465.27torr

Regards!

6 0
3 years ago
How many atoms are in a 1.8 mol sample of Magnesium (Mg)?
Gnom [1K]

Answer:

1.1 × 10²⁴ atoms Mg

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

<em>Identify</em>

[Given] 1.8 mol Mg

[Solve] atoms Mg

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 1.8 \ mol \ Mg(\frac{6.022 \cdot 10^{23} \ atoms \ Mg}{1 \ mol \ Mg})
  2. [DA] Multiply [Cancel out units]:                                                                      \displaystyle 1.08396 \cdot 10^{24} \ atoms \ Mg

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.08396 × 10²⁴ atoms Mg ≈ 1.1 × 10²⁴ atoms Mg

5 0
3 years ago
Read 2 more answers
What would the pH of a solution be if the [H+]= 3.00x10-5 moles/liter
liubo4ka [24]
Are there any options
6 0
3 years ago
Help me please i need the answer now<br>(nonsense report)​
rusak2 [61]

Answer:

Quantitative

  • Words, Measurement, Numbers, Charts, Instruments, Quantity, Data

Qualitative

  • Touch, Quality, Hear, Senses, Description, Exact, Narrative, Analyze

Explanation :

Quantitative Data

  • Can't measure
  • Has numerical value
  • Can campare
  • Do not depend on human eye

Qualitative Data

  • Can't measure
  • Don't have numerical value
  • Can't campare
  • Depend on human eye
3 0
3 years ago
Calculate the number of milliliters of 0.666 M Ba(OH)2 required to precipitate all of the Pb2 ions in 163 mL of 0.656 M Pb(NO3)2
Sliva [168]

Answer:

161 mL

Explanation:

  • Pb(NO₃)₂(aq) + Ba(OH)₂(aq) → Pb(OH)₂(s) + Ba(NO₃)₂(aq)

First we <u>calculate how many Pb⁺² moles reacted</u>, using the<em> given concentration and volume of the Pb(NO₃)₂ solution</em>:

  • 163 mL * 0.656 M = 107 mmol Pb(NO₃)₂

As<em> 1 millimol of Pb(NO₃)₂ would react with 1 millimol of Ba(OH)₂,</em> to precipitate 107 mmoles of Pb(NO₃)₂ we would require 107 mmoles of Ba(OH)₂.

Using the number of moles and the concentration we can <u>calculate the required number of milliliters</u>:

  • 0.666 M = 107 mmol / x mL
  • x mL = 161 mL
5 0
3 years ago
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