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Shkiper50 [21]
2 years ago
15

Oxygen and nitrogen are both gases at room temperature. Explain why oxygen has a greater force of attraction between its particl

es than nitrogen. (Room temperature is 20°C) please help
Chemistry
1 answer:
RideAnS [48]2 years ago
8 0

Answer:

Explanation:

Oxygen molecules and Nitrogen molecules forms in a very similar way. The attraction between particles of oxygen is great due to its very high electronegativity value. Oxygen has a higher electronegative value compared to nitrogen.

Electronegativity of an atom is the relative tendency with which atoms of an element attracts valence electrons in a chemical bond. Valence electrons are used in forming chemical bonds. They can be transferred from one atom to the other or they can be shared.

Oxygen is the second most electronegative atom on the periodic table. To form a bond, it shares the valence electrons in order for its octet to be complete. Pull for the valence electrons between the contributing atoms is very strong due to their large electronegative values. This pull is stronger compared to that between nitrogen atoms.

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6.0L of a gas exert a pressure of 2.5 atm. When the pressure is increased to 10.0atm what is the new volume of the gas
jeka57 [31]

Answer:

<h2>1.5 L</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{6 \times 2.5}{10}  =  \frac{15}{10}  =  \frac{3}{2}  \\

We have the final answer as

<h3>1.5 L</h3>

Hope this helps you

7 0
3 years ago
Which colors form part of the color wheel?
kicyunya [14]

Answer: primary colors are those you can't get by mix in other colors. They are red, blue, and yellow. secondary colors come from mixing two primary colors.

6 0
3 years ago
If the reaction N2 (g) + 3 H2 (g) --&gt; 2 NH3 (g) has the concentrations 1.1 M for nitrogen, 0.75 M for hydrogen and 0.25 M fo
Luba_88 [7]

<u>Answer:</u> The value of K_c is 0.136 and is reactant favored.

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For the chemical reaction between carbon monoxide and hydrogen follows the equation:

N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

The expression for the K_{c} is given as:

K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}

We are given:

[NH_3]=0.25M

[H_2]=0.75M

[N_2]=1.1M

Putting values in above equation, we get:

K_c=\frac{(0.25)^2}{1.1\times (0.75)^3}

K_c=0.135

There are 3 conditions:

  • When K_{c}>1; the reaction is product favored.
  • When K_{c}; the reaction is reactant favored.
  • When K_{c}=1; the reaction is in equilibrium.

For the given reaction, the value of K_c is less than 1. Thus, the reaction is reactant favored.

Hence, the value of K_c is 0.136 and is reactant favored.

4 0
3 years ago
The first law of thermodynamics states that ΔE=Q-W. How is this also a statement of the principle of conservation of energy?
yaroslaw [1]
Hello I took this test just now and got 100% your correct answer would be C. Hope this helps.
4 0
3 years ago
Read 2 more answers
If you double the volume of a sample of gas and then doubled the volume again without changing its pressure, how would this abso
IRINA_888 [86]

Answer:

Explanation:

Increasing Volume while maintaining constant pressure requires a proportional increase in Temperature so the gas pressure will be maintained as constant.

Consider...

V₁ = V₁     V₂ = 4V₁

T₁ = T₁      T₂ = ?

Charles Law => T ∝ V at constant P ... that is, increasing temperature generates a proportional increase in volume to maintain constant pressure.

Empirical Charles Law Relation is ...

V₁/T₁ = V₂/T₂ => T₂ = T₁(V₂/V₁) = T₁(4V₁/V₁) = 4T₁

Increasing Volume of a gas by 4 times requires a 4 times increase in absolute temperature in order to maintain constant pressure.

7 0
2 years ago
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