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QveST [7]
3 years ago
12

Work out the area of this shape

Mathematics
1 answer:
amm18123 years ago
3 0

Answer:

1000

Step-by-step explanation:

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Suppose the number of residents within five miles of each of your stores is asymmetrically distributed with a mean of 25 thousan
ohaa [14]

Answer:

P(\bar X\:>27.8\:thousand)=3.07\%

Step-by-step explanation:

Since the number of residents within five miles of each of your stores is asymmetrically distributed, the distribution of the sample means will be approximately normal with a mean of 25 thousand.

The standard deviation of the sample means is:

\sigma_X=\frac{\sigma}{\sqrt{n} }

\implies \sigma_X=\frac{10.6}{\sqrt{50} }=1.4991

The z value is z=\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n}} }

We plug in the values to get:

z=\frac{27.8-25}{1.4991}=\frac{2.8}{1.4991}=1.87

The area to the right of 1.87 is 1-0.96926=0.03074.

The probability that the average number of residents within five miles of each store in a sample of 50 stores will be more than 27.8 thousand is 3.07%

See attachment.

6 0
4 years ago
Need a list of 6 points geometric shapes
NARA [144]

Answer:

1. Equilateral triangle

2. Isoscles triangle

3. Scalene triangle

4. Right triangle

5. Obtuse triangle

6. Acute triangle

7 0
3 years ago
A random sample is selected from a population with mean μ = 102 and standard deviation σ = 10. For which of the sample sizes wou
chubhunter [2.5K]

Answer:

Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the \bar X with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

\bar X \sim N (\mu ,\frac{\sigma}{\sqrt{n}} )

Based on this rule we can conclude:

a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440

Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean

for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed

Step-by-step explanation:

For this case we know that for a random variable X we have the following parameters given:

\mu = 102, \sigma =10

Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the \bar X with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

\bar X \sim N (\mu ,\frac{\sigma}{\sqrt{n}} )

Based on this rule we can conclude:

a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440

Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean

for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed

8 0
3 years ago
Which of the following is a not a rational number?<br> 1.3<br> 3.1415...<br> 5.25<br> 0.66
Aleks [24]

Answer:

Step-by-step explanation:

3.14159 is irrational because it's a repeating decimal; it cannot be expressed as the ratio of two integers.  All the others can be expressed in that way.

3 0
3 years ago
Read 2 more answers
Please help me thanks very much
emmasim [6.3K]
Answer is D
BE

hope it helps
6 0
3 years ago
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