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serg [7]
3 years ago
8

Help needed for some geometry

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
7 0
In order to create a line parallel to line “I”, rotate line “I” 180° about points “F”. This can be done clockwise or counterclockwise.
Viktor [21]3 years ago
5 0

Answer:

hope this help you. look it once.

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A grain silo has a diameter of 4.4 meters. The height of its cylindrical portion is 6.2 meters.
erastova [34]
Volume of a cylinder = Height x base are
H = 6.2 m
Bae are = π.R² ; Diameter =4.4 m, then Radius = 2.2 m
Base area = π(2.2)²
And Volume=:
V= (6.2).(π,2.2²) = (6.2).(π)(.4.84) = 30.008.π ≈ 94.2 m³
4 0
3 years ago
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Kayla bought a necklace on sale for 35% off. What
Oliga [24]

Answer:

$39

Step-by-step explanation:

60 x 0.39 = 21

60 - 21 = 39

Kayla bought a necklace on sale for $39.

6 0
2 years ago
Describe how you would write 5.04 X 10^6 in standard form.
Margarita [4]

You move the decimal point 6 places to the right because the exponent is positive.

5.04 x 10^6 in standard form is 5040000.

3 0
3 years ago
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How much higher is Checkpoint 5 than Checkpoint 2?
Akimi4 [234]
You have to find the difference in height between both checkpoints. To do this just calculate 196 - 52. Checkpoint 5 is 144 (meters?) higher than Checkpoint 2.
5 0
3 years ago
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Your neighbor has decided to enlarge his garden. The garden is rectangular with width 6 feet and length 15 feet. The new garden
Nana76 [90]

Answer:

Original garden: 42 feet

Enlarged garden: 98 feet

Step-by-step explanation:

Perimeter = length (2) + width (2)

<u>Original perimeter:</u>

P = 15(2) + 6(2)

P = 30 + 12

P = 42 feet

In this problem, similar is proportional, so the new garden will be proportional to the old one.

If the original length was 15 and the new length is 35, then 15 would have had to have been multiplied by 2 1/3. That means you need to multiply 6 by 2 1/3, which is 14. That means the dimensions of the enlarged yard is 14 (width) × 35 (length).

<u>Enlarged perimeter</u>

P = 35(2) + 14(2)

P = 70 + 28

P = 98 feet

4 0
3 years ago
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