Comment
I'm going to take a guess at this and say what you meant is 2401 = 7^(6 - 2x)
Step One
Find out the power of 7 that will equal 2401.
You could do it like this.
7^y = 2401 and just guess at some values.
y 7^y
1 7
2 49
3 7 * 7 * 7 = 343
4 7 * 7 * 7 * 7 = 2401 So the answer is 4
7^4 = 2401
Step 2
Equate the powers.
2401 = 7^(6 - 2x)
7^4 = 7^ (6 - 2x)
4 = 6 - 2x Subtract 6 from both sides.
4 - 6 = - 2x
-2 = - 2x divide by - 2
-2/-2 = x
x = 1 <<<<<<<<<<<<<answer
Answer:
(p + q)² - ∛(h·3k) or (p + q)² - ∛(h·3k)
Step-by-step explanation:
Cube root of x: ∛x
Product of h and 3k: h·3k
Sum of p and q: p + q
*****************************
From (p + q)² subtract ∛(h·3k) This becomes, symbolically:
=> (p + q)² - ∛(h·3k)
Answer:
<u>11t² + 7t + 3</u>
Step-by-step explanation:
⇒ (5t² + 4) - (6t² - 7t + 1)
⇒ 5t² + 4 - 6t² + 7t - 1
⇒ <u>11t² + 7t + 3</u>
Divide both side by 2 ad you get x=80
