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Firlakuza [10]
3 years ago
12

A toy store's percent of markup is 45%. A model train costs the store $50. Find the markup.

Mathematics
2 answers:
mezya [45]3 years ago
5 0

Answer:

$95 is the markup

Step-by-step explanation:

Add 45+50=95

tia_tia [17]3 years ago
3 0

Answer:

$22.50

Step-by-step explanation:

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JUST HELP. HATE MATH! SKSJSJD
PilotLPTM [1.2K]

Answer:

56.5

Step-by-step explanation:

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4 0
3 years ago
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. The mean incubation time for a type of fertilized egg kept at a certain temperature is 25 days. Suppose that the incubation ti
Paul [167]

Answer:

Step-by-step explanation:

Given that the  mean incubation time for a type of fertilized egg kept at a certain temperature is 25 days.

Let X be the incubation time for a type of fertilized egg kept at a certain temperature is 25 days.

X is N(25, 1)

a) Normal curve is in the attached file

b) the probability that a randomly selected fertilized egg hatches in less than 23 days

=P(X

we convert x into Z score and use std normal distn table to find probability

P(X

i.e. we can say only 2.5% proportion will hatch in less than 23 days.

8 0
3 years ago
5 Carla packs 4 pairs of pants, 2 pairs of shorts, and 3 skirts for her vacation.
ratelena [41]

Answer:

D 3:4

Step-by-step explanation:

she packs 3 skirts and 4 pants so it's 3:4. The wording of the question is important (skirts to pants) so you have to put the number of skirts first before pants which is why it IS NOT A.

8 0
2 years ago
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Can anyone pls help me to solve question 2 f and g and pls provide me a explanation I’m with that questions for three days
zvonat [6]

Answer:

  f)  a[n] = -(-2)^n +2^n

  g)  a[n] = (1/2)((-2)^-n +2^-n)

Step-by-step explanation:

Both of these problems are solved in the same way. The characteristic equation comes from ...

  a[n] -k²·a[n-2] = 0

Using a[n] = r^n, we have ...

  r^n -k²r^(n-2) = 0

  r^(n-2)(r² -k²) = 0

  r² -k² = 0

  r = ±k

  a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q

We find p and q from the initial conditions.

__

f) k² = 4, so k = 2.

  a[0] = 0 = p + q

  a[1] = 4 = -2p +2q

Dividing the second equation by 2 and adding the first, we have ...

  2 = 2q

  q = 1

  p = -1

The solution is a[n] = -(-2)^n +2^n.

__

g) k² = 1/4, so k = 1/2.

  a[0] = 1 = p + q

  a[1] = 0 = -p/2 +q/2

Multiplying the first equation by 1/2 and adding the second, we get ...

  1/2 = q

  p = 1 -q = 1/2

Using k = 2^-1, we can write the solution as follows.

The solution is a[n] = (1/2)((-2)^-n +2^-n).

 

5 0
2 years ago
The student council sold jars of mixed nuts at their bazaar they were given 40 empty jars. They paid $19.60 for the nuts and $11
Alex Ar [27]

Answer:

\$1.75

Step-by-step explanation:

Total amount paid for the nuts is $19.60

Total amount paid for the ribbons is $11.20

Profit made on each jar is 98¢= $0.98

Cost price of the nuts and ribbon for the 40 jars is 19.6+11.2=\$30.8

Cost price for nuts and ribbonn for one jar = \dfrac{30.8}{40}=\$0.77

Selling price is the sum of the cost price and profit.

Selling price for one jar = 0.77+0.98=\$1.75

They charged \$1.75 for each jar.

3 0
2 years ago
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