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Aleksandr [31]
3 years ago
13

What is the true solution to 2 In eln5x = 2 In 15? O X=0 O X=3 O X=9 O X= 15

Mathematics
1 answer:
ladessa [460]3 years ago
5 0

9514 1404 393

Answer:

  x = 3

Step-by-step explanation:

Maybe you want the solution ...

  2\ln{(e)}\cdot\ln{(5x)}=2\cdot\ln{(15)}\\\\2\cdot1\cdot\ln{(5x)}=2\cdot\ln{(15)}\\\\5x=15 \qquad\text{divide by 2, take antilog}\\\\x=3 \qquad\text{divide by 5}

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Which ratio is greater than 5/8?<br> 12/24<br> 3/4<br> 15/24<br> 4/12
storchak [24]

Answer:

the answer is 3/4 b.s it's greatest

6 0
3 years ago
Read 2 more answers
In ∆ABC, m∠ACB = 90°, m∠A = 40°, and D ∈ AB such that CD is perpendicular to side AB. Find m∠DBC and m∠BCD.
podryga [215]

Answer:  ∠B = 50°

               ∠BCD = 40°

<u>Step-by-step explanation:</u>

ACB is a right triangle where ∠A = 40° and ∠C = 90°.

Use the Triangle Sum Theorem for ΔABC to find ∠B:

∠A + ∠B + ∠C = 180°

40° + ∠B + 90° = 180°

         ∠B + 130° = 180°

                  ∠B = 50°

BCD is a right triangle where ∠B = 50° and ∠D = 90°.

Use the Triangle Sum Theorem for ΔBCD to find ∠C:

∠B + ∠C + ∠D = 180°

50° + ∠C + 90° = 180°

         ∠C + 140° = 180°

                  ∠C = 40°

8 0
3 years ago
Morris has 2 3/4 gallons of ice tea. He gives 3/7 of it to her friend. How many gallons of ice tea does Morris have left?
lara31 [8.8K]

Answer:

2 \frac{9}{28} gallons of ice tea is left with Morris

Step-by-step explanation:

Morris has 2 3/4 gallons of ice tea. He gives 3/7 of it to her friend.

Morris has 2 3/4 gallons of ice tea

2\frac{3}{4}= \frac{2*4+3}{4}=\frac{11}{4}

He gives 3/7 of it to her friend.

To find how many gallons of ice tea does Morris have left , we subtract 3/7 from 11/4

\frac{11}{4}- \frac{3}{7}

Make the denominators same

\frac{11*7}{4*7}- \frac{3*4}{7*4}

\frac{77}{28}- \frac{12}{28}

\frac{65}{28}

\frac{65}{28} = 2 \frac{9}{28}

7 0
3 years ago
Which equation would you use to find how high the bird is flying?
damaskus [11]

Answer:

The first one

Step-by-step explanation:

An easy way is SOH CAH TOA

SOH is that you use sine if you there is the opposite (in this case the question mark) and hypotenuse (the diagonal line)

CAH is that you use cosine for the adjacent side (1100) and the hypotenuse.

TOA is using tangent for the opposite and adjacent side.

To fine the question mark, you would use tangent. And plug in the given (1100 for the adjacent). So tan45 = x/1100.

If you need more help or clarification, let me know!

6 0
4 years ago
How is the graph of y=(x-1)2 - 3 transformed to produce the graph of y=
Elodia [21]

Answer:

The graph is stretched vertically by a factor of ½, translated left 5 units, and translated up 3 units.

7 0
2 years ago
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