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3 years ago

Consider the linear equation y = 2x - 4. Write an equation in slope-

Mathematics

1 answer:

HACTEHA [7]3 years ago

4 0

Answer: y=2x+14

Explanation:
Y=mx+b
Y= 2x-4
M=2

Y= 2x+b

2 = (2 x -6) + b
2=-12+b
12+2=12+b
-12
14=0+b
14=b

Y=2x+14

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A local citizen wants to fence a rectangular community gardenn. The length of the garden should be at least 110ft,and the distan

Arte-miy333 [17]

The question is incorrect
the correct question is
A local citizen wants to fence a rectangular community garden. The length of the garden should be at least 110 ft,and the distance around should be no more than 380 ft. Write a system of inequality that model the possible dimensions of he garden. Graph the system to show all possible solutions

let
x---------------> the length of the garden
y---------------> the wide of the garden

we know that
x>=110
2x+2y <=380---------------> x+y <= 190

Part A) Write a system of inequality that model the possible dimensions of he garden

the answer part A) is
x>=110
x+y <= 190

Part B) Graph the system to show all possible solutions

using a graph tool
see the attached figure
the solution is the triangle show in the figure

the possible solutions of y (wide) would be between 0 and 80 ft
the possible solutions of x (length) would be between 110 ft and 190 ft

5 0

3 years ago

The probability that the parking lot of a mall is full on a holiday is 0.19. The probability that it is a holiday is 0.29. What

Marta_Voda [28]

19 percent, because holiday is given therefore you just take the percentage of the parking lot

8 0

3 years ago

According to the US Bureau of labor statistics, 7% of US female workers between 16 and 24 years old are paid at the minimum wage

vladimir1956 [14]

Answer:

The Null Hypothesis is $H_o:k_o = 0.07$

The alternative hypothesis is $H_a :k_o \ne 0.07$

Decision rule

If the test staistics is greater than the critical value of significance level then $H_o$ is accepted else $H_o$ is rejected

With the above in mind

The critical value of the significance level which is obtained from the table is

$t_{0.05} = 1.645$

Now since the critical value of significance level is greater than the test staistics then the null hypothesis will be rejected

Conclusion

The information is not enough to back the claim that state differs from the nation

Step-by-step explanation:

From the question we are told that

The percentage of US female workers paid at the minimum wage or less is $k_o =$ 7% = 0.07

The sample size is $n = 500$

The number paid minimum wage or less is x = 42

The significance level is $\alpha =$ 5% = 0.05

Now the probability of getting a US female workers paid at the minimum wage or less is mathematically represented as

$\= k = \frac{x}{n}$

substituting value

$\= k = \frac{42}{500}$

$\= k = 0.084$

The Null Hypothesis is $H_o:k_o = 0.07$

The alternative hypothesis is $H_a :k_o \ne 0.07$

Generally the test statistics is mathematically evaluated as

$z = \frac{\= k - k_o}{\sqrt{\frac{k_o(1-k_o)}{n} } }$

substituting value

$z = \frac{0.084 - 0.07}{\sqrt{\frac{0.07 (1-0.07)}{500} } }$

$z = 1.23$

Now the Decision rule is stated as

If the test staistics is greater than the critical value of significance level then $H_o$ is accepted else $H_o$ is rejected

With the above in mind

The critical value of the significance level which is obtained from the table is

$t_{0.05} = 1.645$

Now since the critical value of significance level is greater than the test staistics then the null hypothesis will be rejected

So the conclusion will be

The information is not enough to back the claim that state differs from the nation

4 0

3 years ago

1/4 / 2 thank you and please help me on this

goldenfox [79]

Answer:

1/8

Step-by-step explanation:

Hope this helps. Pls give brainliest.

4 0

2 years ago

The heights of young women follow a Normal distribution with a mean u = 64.5 inches and standard deviation o = 2.5 inches. The p

mash [69]

Answer:

The heights of young women follow a Normal distribution with a mean u = 64.5 inches and standard deviation o = 2.5 inches. The probability that the mean height of an SRS of 10 young women exceeds 66.5 inches is ＿

normalcdf(66.5, 99999999, 64.5, 2.5)

1 - normalcdf(66.5, 99999999, 64.5, 0.7906)

normalcdf(-99999999, 66.5, 64.5, 2.5)

normalcdf(66.5, 99999999, 64.5, 0.7906)

normalcdf(66.5, 99999999, 0, 1)

1 - normalcdf(66.5, 99999999, 64.5, 2.5)

1 - normalcdf(66.5, 99999999, 0, 1)

normalcdf(--99999999, 66.5, 64.5, 0.7906)

plz need help number 1 2 3 4 5 are pic

8 0

2 years ago