So you have 124 so break it down like this... 100+20+4=124
Best Answer:<span> </span><span>A. Mode
B. Median
C. Mean
the other two are not measures of central tendency.
Data:
4+9/12, 5+3/12, 5+4/12,5+7/12,5+3/12, 5+9/12,6+0/12, 5+4/12,6+0/12, 6+1/12,5+7/12, 5+5/12, 4+5/12
4.4167, 4.75, 5.25{2}, 5.3333{2}, 5.4167, 5.5833{2}, 5.75, 6{2}, 6.0833
n= 13; Σx= 70.75; Σx²= 387.8403; Σx³= 2140.408; Σx^4= 11886.2257
σ= 0.4638; σn-1= 0.4828; Variance=σ²= 0.2152; (σn-1)²= 0.2331
Mean(μ)= 5.4423; range= 1.6667; mid-range= 5.25; median= 5.4167; No Mode Probably right skewed.
Five number summary: Q0= 4.4167, Q1= 5.25, Q2= 5.4167, Q3= 5.875, Q4= 6.0833, IQR= 4.875</span>
How far did the frog jump? the answer is one of the solutions of the quadratic equation
because that's where the frogs height is 0 (y=0) feet.
Use your favorite formula for quadratic equations. I got two solutions: 0 and 30. 0 is clearly the starting point and 30 feet is point where the frog lands.
The height is the maximum of the quadratic form. Use the formula for maximum x of a quadratic: xmax = -b/(2a) = -0.51/(2*0.017) = 15. The maximum at that point is ymax = 3.825
So, the correct answer is (a) 30 ft far and 3.83 high.
√38
Let's name all the squares.
1² = 1 x 1 = 1
2² = 2 x 2 = 4
3² = 3 x 3 = 9
4² = 4 x 4 = 16
5² = 5 x 5 = 25
6² = 6 x 6 = 36
7² = 7 x 7 = 49
8² = 8 x 8 = 64
Okay that's far enough. Now we look for which numbers 38 is in between.
That would be 36 and 49.
But it's asking for where the square root of 38 is, so √36 and √49 ⇒ 6 and 7.
Answer:
D. 9
Step-by-step explanation:
We are told in the question that: The number of tennis balls represented by P(n), in n layers of the square pyramid is given as
P(n) = P(n - 1) + n²
Let's take the first layer
n = 1
P(1) = P(1 - 1) + 1²
P(1) = 1 tennis ball.
It is important to note that the first layers we have one tennis ball.
Let's take the second layer
n = 2
P(2) = P(2 - 1) + 2²
P(2) = P(1) + 2²
Note that: P(1) above = 1
P(2) = 1 + 2²
P(2) = 5 tennis balls
It is important to note that the second layer we have five tennis balls
Let's take the third layer
n = 3
P(3) = P(3 - 1) + 3²
P(3) = P(3 - 1) + 3²
P(3) = P(2) + 3²
Note that: P(2) above = 5
P(3) = 5 + 3²
P(3) = 14 tennis balls
It is important to note that the second layer we have fourteen tennis balls
Let's take the fourth layer
n = 4
P(4) = P(4 - 1) + 4²
P(3) = P(4 - 1) + 4²
P(3) = P(3) + 4²
Note that: P(3) above = 14
P(3) = 14 + 4²
P(3) = 30 tennis balls
It is important to note that the fourth layer we have thirty tennis balls
Hence, the number of tennis balls from the first four layers will be: 1, 5, 14, 30,
So, the number of tennis balls that Coach Kunal could not have is 9.
